The voltage drop across a resistor is equal to the resistance times the current flowing through it. If you do not have a constant current load you cannot use a resistor and must use an active solution. Please read up on ohms law before continuing with your project.
Not possible only if you are going to have a constant current (amp), what you will need is a voltage divider, that is two resistors in serie between your positive and negative 12V+ -^^^^^-1.5-^^^^-0V but no values can be calculated before you know what your max. current is, an estimate R1=120k, R2=15k I agree with crismicro. If you know what the current draw of the load is going to be then its easy to calculate using the formula E / I = R where E= the voltage, I = current, and R= resistance. For example: lets say that you wanted to power a 1.5V light from 12V and you knew that the light required 100 milliamps (.1 Amps). We know that we want to have 1.5 volts to power the light which means that we have to drop 10.5 volts with the resistor. Using the formula gives us 10.5 V / .1 A = 105 Ohms
Start with the load of 2 watts. The power rule says that watts equals volts times amps, or amps equals watts divided by volts, so 2 watts at 120 volts means 0.0167 amps.
Now, look at Kirchoff's current law, which implies that the current in a series circuit is the same at all points. This means that the current in the resistor is also 0.0167 amps.
Now, look at Kirchoff's voltage law, which implies that the sum of the voltage drops in a series circuit adds up to the voltage source. This means that the voltage across the resistor is 157 volts.
Last, look at Ohm's law, which says that resistance is voltage divided by current. 157 volts divided by 0.0167 amps is 9,420 ohms. The nearest standard 5% value to that is 9,100 Ohms.
Before leaving, though, check the power in the resistor. It is 157 volts times 0.0167 amps, or 2.6 watts, so you need at least a five watt resistor.
The resistance in ohms is equal to the voltage drop (9) divided by the current in amps. If the current is constant, that works, but if the current is variable a resistor cannot be used.
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.
A #8 wire with an insulation rating of 75 or 90 degrees C is rated at 45amps respectively.
A #10 wire with an insulation rating of 60,75 or 90 degrees C is rated at 30 amps respectively.
the physical size tells how much power it can dissipate (watts)
Difficult to answer because it depends on the size of the drop.
it is better to use zener diodes or transformators in order to drop 12 vdc to 2 vdc. If you do it with resistor you will waste you power. Voltage formula for resistors in series V1+V2+........+Vn=Vtotal, so 2Vdc+i.R=12Vdc. Determine the current for you supplier and calculate the value of resistance.
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
330 milli ohms
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.
Its dependent what will by rated power of the device (current).
There is no relation between the resistor's ohms value and its size. The power of the resistor can be seen by its size. If the power is too small, the resistor can be destroyed.
Greater value resistor will absorb more voltage than smaller value. The more voltage absorb with same value current flow, the larger body mass resistor will require. Body size depends on type of resistor (material resistor is made of).
there might be ways to get the power rating by measuring the size of the resistor. but as the physical size of the resistor increases, its power rating also increases..
use Ohm's law: to drop 2 volts, V = I x R 2 = current x resistance resistance = 2 / current. So you need to know the current
This question cannot be answered because you did not specify the current.
A potentiometer.
A: A resistor size is determined by the usage or its power dissipation. the bigger the size the more power it can dissipate due to the extra surface. SIZE is a function of power dissipation and has nothing to do with its value