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Show that 2222 to the power 5555 plus 5555 to the power 2222 is divisible by 7?
Wiki User
∙ 11y ago
2222= 3 mod 7
5555 = 4 mod 7
2222^5555 + 5555^2222 = (3^5)^1111 + (4^2)^ 1111
as it is a^n + b^n and n is odd so it is divisible by (a+b)
3^5 + 4^ 2 = 259
hence by 7 as 7 is a factor of 259
Wiki User
∙ 11y ago
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