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For a series circuit, the applied voltage equals the sum of the voltage drops

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Q: The applied voltage in a circuit equals the sum of the circuits individual what?
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What is total voltage in a series circuits?

In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.


What are the 2 kind of circuit?

The two basic circuit types are series circuits and parallel circuits. In a series circuit, all the current flows through each component, and each one drops some of the applied voltage. In a parallel circuit, the applied voltage is dropped across each parallel component and current "splits" so some flows through each component.


If you add the IR drop or voltage drop of each individual resistance in a series circuit is it equal to the applied voltage?

Yes


What limits the current that flows through a circuit for a particular appllied DC voltage?

The voltage applied and the resistance across it.


What is the definition of applied voltage?

Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".


What is voltage drop in an electrical circuit?

When a current flow on a conductor , or load or resistor, some voltage will drop across that load or resistor.AnswerA voltage drop is the potential difference appearing across individual components in a circuit, necessary to drive current through those components. The sum of the individual voltage drops around a series circuit will equal the supply voltage applied to that circuit.


What is the applied voltage to a resistive capacitive circuit?

this is the amount of voltage a circuit can hold.


When an alternating voltage is applied to purely resistive circuit what happens?

When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.


The resistor in an R-L series circuit has a voltage drop of 53V and the inductor has a voltage drop of 28V what is the applied voltage of the circuit?

The applied voltage is 53+28 = 81V.


How is voltage spread out in series circuit?

By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.


Can the total of the voltage drops across the loads of a series circuit ever exceed the total of the source voltages applied to that circuit?

No. But bear in mind that, in the case of a.c. circuits, 'total', means the phasor (vectorial) sum of the voltage drops, NOT the algebraic sum.


Why do the voltage drops of an inductor and a lamp in a series ac circuit not equal the applied voltage?

The voltage is greater than the applied voltage, why?