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The internal energy of an ideal gas depends on?
internal energy of an ideal gas is a function of its temprature only, according to joule's law
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A substance whose molecules do not take up space or interact with one another. PV = nRT The Ideal Gas Law is the chemistry law that combines the other gas laws (Charles's La…w and Boyle's Law). Symbolically it is: PV = nRT . Where: . P is the pressure of the gas (in atmospheres, ATM) . V is the volume of the container (in liters, L) . n is the number of moles of gas in the container (in moles) . R is universal gas constant (which is 0.0820574587 L Â· ATM Â· K -1 Â· mol -1 ) . T is the temperature of the gas (in Kelvin) See the Web Links for more information about the Ideal Gas Law, as well as Charles's Law and Boyle's Law.
F(T,V,N) = (3/2)(NkT) - TkN((3/2)ln((3/2)kT)+ln(V/N)+x)
F=U-TS where F is the Free energy, U is energy, T temperature and S entropy
The one and only macroscopic thermodynamic property that the internal energy of an ideal gas depends on is its temperature.
It increases. hope this helps xx :)
To prove this, we will have to use 3 equations, 2 of them related to ideal gases: (i) pV = nRT (ii) p = 1/3 d (iii) Ek = 1/2 mv2 First of all, an ideal gas has no intermolecu…lar forces. Thus, its molecules have no potential energy. The internal energy of any system can be defined as the sum of the randomly distributed microscopic potential energy and kinetic energy of the molecules of the system. It is thus evidently clear that the internal energy of an ideal gas is entirely kinetic. (Ep being zero) So, U = 1/2 m (for an ideal gas) From (i) and (ii), = 3p/d = 3pV/m = 3nRT/m (d= m/V) Substituting in the appropriate equation, we get: U = 1/2 m (3nRT/m) U = 3/2 nRT From the above equation, it can be concluded that for a fixed mass of an ideal gas, internal energy is proportional to the thermodynamic temperature. (fixed mass such that n is constant)
The first law of thermodynamics states that: DU = DQ + DW where DU is the increase in the internal energy of the gas DQ is the heat supplied to the system and DW is the work d…one ON the system For an adiabatic process, DQ = 0 Therefore, DU = DW It can be thus easily seen that for the internal to increase (DU +ve), DW must be positive, that is work has to be done on the system (in this case the ideal gas). Hence, the gas should be compressed.
Because they have a lot of it but don't have a lot of water (so they can't build for instance dams to produce energy).
What happens to the internal energy of an ideal gas when it is heated from 0 degrees celsius to 4 degrees celsius?
If it's not allowed to expand, then its internal energy increases by about 1.46% .
Potential energy and internal energy are different things and unrelated - except when a process converts one to the other. In most processes involving gases, the density of th…e gas is so low that changes in potential energy (which depend on total mass times change in height) are not significant in comparison to changes in the internal energy, so we neglect it in out calculations.
49, 200 (apex)
Internal energy is an extensive state function. That means it depends on how much of a substance you have but if you fix the composition, pressure, temperature, volume, and (i…n the case of a system at a phase equlibrium point, like water at the freezing point) the phase of a system, the specific internal energy will be constant. If you take a closed system and change the volume of it, you will be doing work (or allowing the system to do work) and the internal energy can change - so - yes - internal energy of a system depends upon volume. Also, if you fix the composition, temperature, pressure, and phase of a homogeneous mass but change the volume, you will increase the amount of mass you included in the system, thus changing the total internal energy (because it is, after all, an extensive function).
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When you boil a liquid and it turns into an ideal gas where does the energy go because the temperature remains constant so kinetic energy is the same and ideal gases don't have potential energy?
It turns into latent heat - the latent heat of evaporation. This energy is recovered when the gas condenses back into a liquid.