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The internal energy of an ideal gas depends on?
internal energy of an ideal gas is a function of its temprature only, according to joule's law
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If 800 joules of heat are added to a gas in an isochoric process what is the change in its internal energy?
If 400 joules of heat are added to a gas in an isochoric process what is the change in its internal energy?
If 100 joules of heat are added to a gas in an isochoric process what is the change in its internal energy?
The change would be 100 joules, because an isochoric system can not perform the work.
A substance whose molecules do not take up space or interact with one another. PV = nRT The Ideal Gas Law is the chemistry law that combines the other gas laws (Charles's La…w and Boyle's Law). Symbolically it is: PV = nRT . Where: . P is the pressure of the gas (in atmospheres, ATM) . V is the volume of the container (in liters, L) . n is the number of moles of gas in the container (in moles) . R is universal gas constant (which is 0.0820574587 L Â· ATM Â· K -1 Â· mol -1 ) . T is the temperature of the gas (in Kelvin) See the Web Links for more information about the Ideal Gas Law, as well as Charles's Law and Boyle's Law.
To prove this, we will have to use 3 equations, 2 of them related to ideal gases: (i) pV = nRT (ii) p = 1/3 d (iii) Ek = 1/2 mv2 First of all, an ideal gas has no intermolecu…lar forces. Thus, its molecules have no potential energy. The internal energy of any system can be defined as the sum of the randomly distributed microscopic potential energy and kinetic energy of the molecules of the system. It is thus evidently clear that the internal energy of an ideal gas is entirely kinetic. (Ep being zero) So, U = 1/2 m (for an ideal gas) From (i) and (ii), = 3p/d = 3pV/m = 3nRT/m (d= m/V) Substituting in the appropriate equation, we get: U = 1/2 m (3nRT/m) U = 3/2 nRT From the above equation, it can be concluded that for a fixed mass of an ideal gas, internal energy is proportional to the thermodynamic temperature. (fixed mass such that n is constant)
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F=U-TS where F is the Free energy, U is energy, T temperature and S entropy
0. An ammeter is placed in series with the circuit in question; if its' internal resistance is high, it will change the current flow, thus making the measurement meaningless. …For the same reason an ideal voltage meter will have infinite resistance.
That conforms to all of the assumptions of the kinetic theory.
Strictly speaking no, as an ideal gas is simply a theoretical device. Though it can be treated as an ideal gas to an extent.
49, 200 (apex)
That conforms to all of the assumptions of the kinetic theory