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The only way to eliminate the arbitrary constant is if an extra equation is given that gives a value to y at a specific x.

Example:

Solve the differential equation, dy/dx = 2x + 3, where y = f(x), with condition, f(1) = 3.

Separate the variables and integrate:

dy = (2x + 3)dx, ∫ dy = ∫ (2x + 3)dx, y + C1 = x2 + 3x + C2.

C1 and C2 are arbitrary, so they combine into one constant, C:

y = x2 + 3x + C

Find C by substituting the values of the given condition into the above equation:

3 = 12 + 3(1) + C = 1 + 3 + C = 4 + C, so C = -1

Our final answer then, with the given condition, is:

y = x2 + 3x - 1

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