t(n) = 3n-1 , where n = 1, 2, 3, ...
t(5) = 81
t(6) = 243
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
The difference between the numbers is increasing by 1 every time. Therefore, since the difference between the last two numbers is equal to 6, the difference between the next two numbers will be 7. 20 + 7 = 27. Therefore the next number in the sequence will be 27.
1 and 27 3 and 9
The LCM of the given two numbers is 27
1 & 27; 3 & 9.
1 and 0
81, 243, 729 The numbers are being multiplied by 3.
1 x 27, 3 x 9
1 x 27, 3 x 9
1 and 27 do.
1 x 27 3 x 9
64, 125 and 216