It's the takeoff safety speed. The speed at which the aircraft may safely become airborne with one engine inoperative.
It is the speed at which a plane can achieve sufficient lift to take-off and safely climb with one engine failed during take-off roll after v1.
-23
No you cant
If you mean the first to reach space, they say that a V2 German rocket reached Low-earth-orbit during testing in 1942.
If you mean the first to reach space, they say that a V2 German rocket reached Low-earth-orbit during testing in 1942.
Werner von Braun
The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow, acceleration a = (v2 - v1)/t from which v2 = v1 + at The distance covered during t time d = vav x t, where vav refers to average velocity in the process from v1 to v2. For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we get d = (v1 + v2)/2 x t from which, v2 = 2d/t - v1 If we take the constant acceleration to be zero, a = 0, you can see that the second equation we wrote becomes, v2 = v1 (There is no acceleration), so our equation for the distance d becomes, d = v1 x t = v2 x t
V2 is the actual speed at 35 ft above the runway as demonstrated in flight during takeoff with one engine inoperative. a.k.a. - takeoff safety speed.
about a week, age: 5-8 --mewMew
The lift off speed is dependant upon the weight of the aircraft. The heavier the aircraft the higher the speed. At maximum take off weight of 875,000 lbs (396,890 kgs) Vr (rotation speed) will be about 175 knots and V2 about 185 knots.
5 * 10**-12 mol 32 * 10**-9 mol Concentration (M) * Volume (L) = mols C1*V1=C2*V2 (5*10**-12)*V1=(32*10**-9)*V2 (5*10**-12)*V1/(32*10**-9)=V2 (5*10**-3)*V1/32=V2 The volume of the 5 picomolar solution that you wish take = V1 The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2 Take V2, and place into graduated cylinder and fill to V1.
HISTORIA AUGUSTA V2. has written: 'HISTORIA AUGUSTA V2'