If a 200 mA power supply is used on a circuit needing 2 amp it would overload the power supply. Two amps equates to 2000 milliamps. Trying to pull 2000 milliamps from a device that is only capable of supplying 200 milliamps is not advisable. The excessive current draw would most likely burn the wires open and render the power supply useless.
Maximum power transfer happens in a circuit when the resistance of the circuit equals the reactance. Impedance Z = R + jX. At R=X, maximum power transfer happens.
battery
That depends what circuit it is in. If it is in a sweep circuit (vertical/horizontal) no because it will change the frequency of the circuit. If it is in a power supply circuit, probably yes becuase it is probable only being used as a filter. BUT if that leg of the power circuit supplies a sweep circuit, no.
One possibility for what affects the voltage, is how many light bulbs, motors etc you have in the circuit causing the energy ( voltage ) to be shared.
A capacitor is placed across the supply of a fluorescent lamp circuit to correct the power factor
Everything would work as designed if you used a 2 amp power supply for a 200 ma circuit.It's important to not go OVER the designed capacity of the power supply, and in fact, it's a good idea to make sure the power supply has at least double the capacity of the load current.
A break in an electrical circuit will cause the circuit's load to stop operating.
That would depend on the power supply.
is an embedded circuit or stand alone unit the function of which is to supply a stable voltage to a circuit or device that must be operated within certain power supply limits .
A device or circuit that provides power to the rest of the circuit or system is called a power supply,
because the power still are in circuit of the motherboard and you have to drain the system
Both take current and energy from the power supply and dissipate power.
Usually a circuit is connected to a power source, which could be a battery or an outlet. When this happens current flows through the circuit. The power supply raises electrical charges through the required potential difference, and then in the circuit the charges flow down the potential gradient giving up their energy.
a power supply (eg: battery) and a load (eg: resistor) even a piece wire shorting two terminals of the power supply is a closed circuit
Maximum power transfer happens in a circuit when the resistance of the circuit equals the reactance. Impedance Z = R + jX. At R=X, maximum power transfer happens.
The power in the circuit will increase.
Well, first of all, if the resistance of the circuit is 10 ohms and you connect 10 volts to it,then the current is 1 Amp, not 2 . So either there's something else in your circuit thatyou're not telling us about, or else the circuit simply doesn't exist.-- If you connect some voltage to some resistance, then the resistance heats up anddissipates (voltage)2/resistancewatts of power, and the power supply has to supply it.-- If there is some current flowing through some resistance, then the resistance heats up anddissipates (current)2 x (resistance)watts of power, and the power supply has to supply it.-- If there's a circuit with some voltage connected to it and some current flowingthrough it, then the resistance of the circuit is (voltage)/(current) ohms, the partsin the circuit heat up and dissipate (voltage) x (current) watts of power, andthe power supply has to supply it.There's no such thing as "the power of a circuit". The power supply supplies thecircuit with some amount of power, the circuit either dissipates or radiates someamount of power, and the two amounts are equal.