Adding a resistance in parallel to another resistance will reduce the equivalent resistance.
Parallel Equation:
R1 = 10Ω
R2 = 20Ω
Req = R1R2/(R1+R2) = (1/R1+1/R2)-1
Req = 10•20/(10+20) = 6.67Ω
In that case, the resulting (equivalent) resistance will be less than any of the individual resistances.
The equivalent resistance is calculated by the formula:
1 / R = 1 / R1 + 1 / R2 + 1 / R3 ...
Where "R" is the equivalent resistance you want to calculate, and R1, R2, etc. are the resistance values of the individual resistors.
Increases
In a parallel circuit the current divides when it comes to a junction. Part of the current flows through one branch and the other part flows through the other.When the two branches have the same resistance, the same current flows through each branch.When the two branches have different resistances, a bigger current flows through the branch with the smaller resistance - it's just easier this way!Hope i helped ;)
The circuit resistance is likely to gradually drop and in such case it will cause the circuit to burn down.
It shortens
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
What do you mean by a 'parallel delta' circuit -is there such a connection.
No change in supply voltage as additional resistance is connected in parallel circuit.
The voltage drop across each resistance will go up, and the current through the circuit will go down.
current decreases and resistance increases
That has no effect on the resistance. The current doubles also.
If the resistances to big in any circuit the circuit will become increasingly harder and eventually will break the circuit. An example of this is when the filament in an incandescent lightbulb burns out.
The resistance R of two or more resistances in parallel is given by: R = 1/(the sum of the reciprocals of the individual resistances). I.e. if each resistor be designated as r(number), then 1/R = 1/r1 + 1/r2 + ... + 1/rn The material from which the components are made is not important in the formula, but may be significant to specific circuit design criteria.
Increases
This happens because the total parallel resistance is lower than the individual resistors that make up the group of parallel resistors. When you add another parallel load, the resistance of that parallel group lowers and as result increases the current for the rest of the circuit.
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
In a parallel circuit the current divides when it comes to a junction. Part of the current flows through one branch and the other part flows through the other.When the two branches have the same resistance, the same current flows through each branch.When the two branches have different resistances, a bigger current flows through the branch with the smaller resistance - it's just easier this way!Hope i helped ;)
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'