# What is a c plus number grade?

# How do you create an random number in C plus plus?

Use the random number generator classes. #include #include std::default_random_engine generator ((unsigned)time(0)); // seed the generator std::uniform_int_distribution distribution (0, 100); // set the closed range int r = distribution (generator); // pick a random number from 0 to 100 (in…clusive) Any device can be used to seed the generator. Here, we've simply used the current time. If you don't seed the generator, it will generate the same sequence of random values every time the program is run. (MORE)

# How do you reverse a 6 digit number in C plus plus?

The number of digits is immaterial, the principal is exactly thesame. The key to reversing any number is in the followinguser-defined function: uint reverse(uint num) { uint rev=0; while(num) { rev*=10; rev+=num%10; num/=10; } return(rev); } The following code demonstrates how to reverse a 6 digit… numberentered from the console. #include #include #include typedef unsigned int uint; uint reverse(uint num) { uint rev=0; while(num) { rev*=10; rev+=num%10; num/=10; } return(rev); } int getrange(uint digits,uint& min,uint&max) { if(!digits) return(-1); min=1; while(--digits) min*=10; max=min*10-1; return(0); } uint inputnumber(const std::string prompt,const uint min,const uintmax) { using namespace std; uint result=0; while(1) { cout (MORE)

# Which is higher in graded c or c plus?

Ofcourse higher graded is C++ between C and C++ because C++ is advance level of C, it is derived from C language.

# C plus plus program to reverse the given numbers?

int RevNum( int num ) { const int base = 10; int result = 0; do {.
result *= base;.
result += num % base;.
} while( num /= base); return( result );.

# How do you swap two numbers in c plus plus?

void swap(int &x, int &y) { x ^= y ^= x; } - or - void swap(int &x, int &y) { int t = x; x = y; y = t; }

# A c plus plus program illustrating rational number?

int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);

# How do you reverse a 5-digit number in c plus plus?

It really does not matter how many digits there are, the principal is exactly the same. The following function is the most efficient way to reverse any whole number in the range -2,147,483,648 to 2,147,483,647, inclusive (assuming a 32-bit integer). To increase the range, create separate functions t…o cater for 64-bit and 128-bit integers. Converting the number to a string and reversing the string is also an option (see previous answer, below), however it is by far the least efficient method of reversing a whole number. int RevNum( int num ) { const int base = 10; int remain = 0; int result = 0; do {.
remain = num % base; result *= base;.
result += remain;.
} while( num /= base); return( result );.
} Previous Answer This is assuming the number is decimal. There are several approaches to the problem, depending on the resources you have available or wish to use to solve it. One way to achieve this is to isolate the digits through modulo division and the remultiply them in the desired order: rev = ((original % 10) * 10000) + (((original / 10) % 10) * 1000) + (((original / 100) % 10) * 100) + (((original / 1000) % 10) * 10) + (original / 10000); .
An alternative that doesn't look so messy: int temp = original; int rev = 0; for (int i=0;i (MORE)

# C plus plus program to find prime number?

Here's an example. I've included analysis. #include #include #include int main(void) { /* User inputs high and low ends of range to search. / This could easily be done as function inputs, if / if so desired. */ int testprime,testdivisor, minprime, maxprime; printf("Search for… primes between:\nLow end: "); scanf("%d",minprime); printf("Top end: "); scanf("%d",maxprime); int isprime; // 0 indicates a number is not prime.. for(testprime=minprime;testprime (MORE)

# What is the equivalent number of a letter C in C plus plus?

The character code for C is 'C'. Believe it or not, the compiler will automatically cast all literal characters to their equivalent character code so there's no need to remember every code by heart. However, the decimal equivalent of 'C' is character code 67, which is 43 in hexadecimal and 103 in oc…tal. But using a literal char makes your code much that much easier to understand. consider the following code: bool compare(char ch) { return(ch67); } Unless you happen to know that 67 is the character code for 'C', it's not exactly clear what this function does. bool compare(char ch) { return(ch'C'); } Now it's patently obvious what it does. Note also that lower case character codes are always 32 decimal greater than their uppercase equivalent. Thus 'c' is character code 99 and therefore 99-67 is the same as saying 'c'-'C' (both expressions will evaluate to decimal 32). Therefore to convert character ch to uppercase, subtract 32 if 'a' (MORE)

# How do you find absolute number in C plus plus?

For floating point numbers, do #include and use std::abs(). For integers do #include and use std::abs().

# How do you divide 2 numbers using c plus plus?

Basic code in C++ for division would be: int a = 2; int b = 2; int c = a / b; A more advanced application would be to allow the user to specify the variables: #include int num1; int num2; std::cout > num1; std::cout > num2; std::cout

# Greatest of 3 numbers in C plus plus?

The most common way is to use a function that returns the max of two values, passing the result of that into the same function along with the third value. The other solution is to pass all three into a single function call. It makes no real difference which you use as inline expansion would eliminat…e all the function calls anyway. It's just a question of which is easier to read and understand. The single call is more complex to implement but is easier to call, while the double call is easier to implement but more complex to call. However, the double call can easily be extended to a triple call for the max of 4 numbers, and so on. #include int max(int x, int y ) { return(x>y?x:y); } int max(int x, int y, int z ) { return(x>y?x>z?x:z:y>z?y:z); } int main() { int x=1, y=2, z=3; std::cout (MORE)

# How do you print a pyramid of numbers C plus plus?

include #include #include #include #include void print_pyramid (const std::vector& v) { size_t tiers {v.size()}, spaces {1}, row {1}; while (tiers > row) { tiers -= row++; ++spaces; } tiers = spaces + 1; std::vector::const_iterator i=v.begin(); for (size_t tier=0; tier!=tiers; ++tier) { if… (spaces) std::cout (MORE)

# Palindrome number in c plus plus programming?

There are several ways to determine if a string is a palindrome ornot. Typically, you must first ignore all spacing, capitalisationand punctutation within the string, which can be done by copyingthe string, character by character, ignoring all non-alphanumericcharacters. You then point to the first …and last characters in themodified string and, so long as both characters under the pointersare the same, work the pointers towards the middle of the stringuntil the pointers either meet in the middle or they pass eachother. That is, if the string has an odd count of characters, thepointers will meet at the middle character, otherwise they willpass each other. At that point you can say with certainty thestring is a palindrome. If the characters under the pointers differat any time, then the string is not a palindrome. This is fairlystraightforward to program. A more interesting problem is when you have to locate the longestpalindrome within a string which is not itself a palindrome. Forinstance, the string "Madam, I'm Adam is a palindrome" is not apalindrome, but it does contain one: "Madam I'm Adam". In this casewe cannot point to the first and last characters and work towardsthe middle. Instead, we have to test every possible substring ofthe string. We do this by starting at the first character and treatit as if it were actually the middle character of a palindrome, andthen move our pointers to the left and right of this characterwhile the characters match. When they no longer match, or one ofthe pointers has reached either end of the string, we store thelongest palindrome found up to that point and then move onto thenext character and treat it as the middle character. If we continuein this manner, treating every character as if it were the middlecharacter of a palindrome, we will eventually locate the longestpalindrome. The problem with this approach is when the longest palindrome hasan even number of characters instead of an odd number. To getaround this we simply place a single space between each character,and treat each of those as being the middle character as well. Whena palindrome is found, we simply remove the spaces. In this way wecan use exactly the same algorithm to cater for both odd and evencharacter palindromes. The only remaining problem is when we wish to print the palindromeitself. Since this will be a substring of the original string, wecannot use the modified string we used to locate the palindrome.One way to get around that is to store the original positions ofeach letter in an array of indices, and use that array to determinewhere the substring lies with in the original string. The following program demonstrates this technique in full. The keyfunction is the ispalindrome() function, which accepts a lower-casecopy of the string (including the original spacing an punctuation),and a vector that contains the indices of each letter within thestring (ignoring puctuation and spacing), separated by -1 values(representing the implied spaces between each letter). The posvalue tells the function which index of the vector is to be treatedas the middle character of the potential palindrome, while x and yare output parameters that determine the start and end of thepalindrome within the vector. The function returns true if apalindrome was found, and the x and y values can be used to extractthe palindrome from the original string, using the indices storedin the vector. Note that when the search for a palindrome fails, westep back the x and y indices by one, and if the vector index is-1, then we step back another index. We then test the x and yvalues to see if they indicate a palindrome was found or not. The strip() function is another key function. This generates thevector from the lower case copy of the original string. Although wecould eliminate the -1 values at the start and end of the vector,it's simpler to just leave them in. You will note that the program can cater for strings that arethemselves palindromes, as well as strings that containpalindromes. #include #include #include using namespace std; string input_string(string prompt) { cout (MORE)

# C plus plus program for finding practical numbers?

include #include #include #include template class subset { public: using value_type = typename _Ty::const_iterator; using subset_type = std::vector; using iterator = typename subset_type::iterator; using const_iterator = typename subset_type::const_iterator; using reverse_iterator = typename… subset_type::reverse_iterator; using const_reverse_iterator = typename subset_type::const_reverse_iterator; using size_type = typename subset_type::size_type; inline explicit subset (const _Ty& set); subset (const subset& source) = delete; subset (subset&& source) = delete; subset& operator= (const subset& source) = delete; subset& operator= (subset&& source) = delete; const subset_type& first (size_type size); const subset_type& next (void); private: size_type m_size; subset_type m_set; subset_type m_subset; const_iterator find (const value_type& value) const; }; template subset::subset (const _Ty& set): m_size (set.size()), m_set (), m_subset () { for (value_type it=set.begin(); it!=set.end(); ++it) m_set.push_back (it); } template typename subset::const_iterator subset::find (const value_type& value) const { const_iterator it=m_set.begin(); while (it!=m_set.end() && *it!=value) ++it; return it; } template const typename subset::subset_type& subset::first (size_type count) { assert (0U < count); assert (count (MORE)

# C plus plus program that finds the minimum number?

template size_t min(const T a[], const size_t size) { // assume first element (index 0) has the smallest value size_t selected=0; // scan remainder of array looking for anything smaller than selected for (size_t right=selected+1; right

# What is the function of the number sign in c plus plus?

If I understand your question, the number sign for a value or number can represent either a positive quantity or a negative quantity when attached to a native data type. For other data types it can represent the opposite of, or can be an overloaded operator (either unary or binary) that can take on… any representation you with the operator to have (which can include non-intuitive reasoning's). (MORE)

# C plus plus code that determine prime number?

include main() { int a; couta; cout

# Testing c plus plus code prime number?

Use the following function to determine if a whole number is prime, including negative values: bool isprime(int p) { if(p

# C plus plus program to reverse the digits of a number?

int RevNum( int num ) { const int base = 10; int result = 0; do {.
result *= base;.
result += num % base;.
} while( num /= base); return( result );.

# To print automorphic number in c plus plus language?

include #include bool is_automorphic(const size_t num) { std::stringstream ss; std::string strnum, strsqr; size_t square = num*num; ss > strnum; ss.clear(); ss > strsqr; return strnum==strsqr.substr(strsqr.size()-strnum.size(),strnum.size()); } void process (const size_t num) { if (is_automorp…hic(num)) std::cout (MORE)

# What number grade is a c plus?

A C plus is any grade between 75 and 79. B minus would then be anything from an 80 to an 84, and so on and so forth.

# Sum and average of n numbers in C plus plus?

include #include using std::cout; using std::cin; using std::endl; using std::vector; int main() { int counter = 1; cout

# Binary to octal numbers in c plus plus codes?

The following code demonstrates one way to convert from binary to octal based on user input: #include #include typedef unsigned int uint; std::string input(std::string prompt) { std::cout

# Write c plus plus programme for number is palindrome or not?

There are several ways to determine if a string is a palindrome ornot. Typically, you must first ignore all spacing, capitalisationand punctutation within the string, which can be done by copyingthe string, character by character, ignoring all non-alphanumericcharacters. You then point to the first …and last characters in themodified string and, so long as both characters under the pointersare the same, work the pointers towards the middle of the stringuntil the pointers either meet in the middle or they pass eachother. That is, if the string has an odd count of characters, thepointers will meet at the middle character, otherwise they willpass each other. At that point you can say with certainty thestring is a palindrome. If the characters under the pointers differat any time, then the string is not a palindrome. This is fairlystraightforward to program. A more interesting problem is when you have to locate the longestpalindrome within a string which is not itself a palindrome. Forinstance, the string "Madam, I'm Adam is a palindrome" is not apalindrome, but it does contain one: "Madam I'm Adam". In this casewe cannot point to the first and last characters and work towardsthe middle. Instead, we have to test every possible substring ofthe string. We do this by starting at the first character and treatit as if it were actually the middle character of a palindrome, andthen move our pointers to the left and right of this characterwhile the characters match. When they no longer match, or one ofthe pointers has reached either end of the string, we store thelongest palindrome found up to that point and then move onto thenext character and treat it as the middle character. If we continuein this manner, treating every character as if it were the middlecharacter of a palindrome, we will eventually locate the longestpalindrome. The problem with this approach is when the longest palindrome hasan even number of characters instead of an odd number. To getaround this we simply place a single space between each character,and treat each of those as being the middle character as well. Whena palindrome is found, we simply remove the spaces. In this way wecan use exactly the same algorithm to cater for both odd and evencharacter palindromes. The only remaining problem is when we wish to print the palindromeitself. Since this will be a substring of the original string, wecannot use the modified string we used to locate the palindrome.One way to get around that is to store the original positions ofeach letter in an array of indices, and use that array to determinewhere the substring lies with in the original string. The following program demonstrates this technique in full. The keyfunction is the ispalindrome() function, which accepts a lower-casecopy of the string (including the original spacing an punctuation),and a vector that contains the indices of each letter within thestring (ignoring puctuation and spacing), separated by -1 values(representing the implied spaces between each letter). The posvalue tells the function which index of the vector is to be treatedas the middle character of the potential palindrome, while x and yare output parameters that determine the start and end of thepalindrome within the vector. The function returns true if apalindrome was found, and the x and y values can be used to extractthe palindrome from the original string, using the indices storedin the vector. Note that when the search for a palindrome fails, westep back the x and y indices by one, and if the vector index is-1, then we step back another index. We then test the x and yvalues to see if they indicate a palindrome was found or not. The strip() function is another key function. This generates thevector from the lower case copy of the original string. Although wecould eliminate the -1 values at the start and end of the vector,it's simpler to just leave them in. You will note that the program can cater for strings that arethemselves palindromes, as well as strings that containpalindromes. #include #include #include using namespace std; string input_string(string prompt) { cout (MORE)

# Program to sort numbers in c plus plus?

/* Bubble sort: code snippet only nos to be sorted are in the array named 'n' of size 'N' for(int i=0;iv;j--) n[j+1]=n[j]; n[j+1]=v; } */

# What is the c plus plus program to add two numbers?

include int main() { double num1 = 0.0; std::cout > num1; double num2 = 0.0; std::cout > num2; std::cout

# Greatest of n numbers-c plus plus program?

include using namespace std; int main() { int N; coutN; int arr[N]; cout

# Bubblesort in c plus plus enter number?

Optimised bubble-sort algorithm for use with small vectors of any type: template void bubble_sort(std::vector& v) { unsigned size = v.size(); if (1

# Program that will interchange the input numbers in c plus plus '?

include template void exch(T& a, T& b) { T temp = a; a = b; b = temp; } int main() { int x=4, y=2; exch(x,y); }

# How do you calculate the average of three numbers in c plus plus?

The same way you do it in any language: divide the sum by three..
int x, y, z, average;.
x = 1;.
y = 3;.
z = 5;.
average = (x+y+z)/3;.

# How do youWrite a c plus plus program that computes grading system?

Use the following function. Adjust the percentage marks to suit the grades in your university or region. The following applies in most Nova Scotia universities: std::string get_grade(unsigned mark) { if (mark>=90) return "A+"; if (mark>=85) return "A"; if (mark>=80) return "A-"; if (mark>=77) re…turn "B+"; if (mark>=73) return "B"; if (mark>=70) return "B-"; if (mark>=65) return "C+"; if (mark>=60) return "C"; if (mark>=55) return "C-"; if (mark>=50) return "D"; return("E"); } Example usage: unsigned mark = 62; // out of 100 std::cout (MORE)

# Sum of two numbers in c plus plus?

include int main { int x=40, y=2; std::cout

# Program to find Factors of a number in c plus plus?

The following example returns a list of all factors for a given natural number, n. Zero is not a natural number thus an empty list is returned in this case. list nfactor(unsigned int n) { // list of factors to return list f; // n must be >=1 (natural numbers only) if( n ) { // 1 is always a facto…r f.push_back(1); // natural number 1 is a special case (only 1 factor) if( n>1 ) { // Calculate remaining factors from 2 to n/2 for(unsigned int c=2; c1 ) { // Calculate remaining factors from 2 to a/2 for( int c=2; c (MORE)

# What is the program for prime number in c plus plus?

include #include bool is_prime (const unsigned num) { if (num "Enter a natural number: "; unsigned num; std::cin

# What is the factorial of a given number in C plus plus?

The factorial of a given number in C++ is the same as the factorial for a given number in mathematics. That is, the language is immaterial -- the algorithm remains the same. The factorial of positive integer n is denoted n! and is the product of all positive integers less than or equal to n. Thus …the factorial of 5 is 5!, which 5 x 4 x 3 x 2 x 1 = 120. Although the factorial of a given number is a recursive operation (and is often used to demonstrate recursive functions), an iterative approach uses less memory. The basic algorithm is to successively multiply a variable initialised to 1 by all the integers from 2 to n. In C++ this can be implemented as follows: int factorial(const int number) { int product = 1; int multiplier = 1; while (multiplier++ (MORE)

# C plus plus program to swap two numbers?

include int main() { int x=40; int y=2; // Swap the values of x and y: int temp=x; x=y; y=temp; }

# What function in c plus plus that only accept numbers?

All data is digital in a digital computer -- the numbers are merely an abstraction for real objects, even if those objects are non-numeric (such as people, animals, cars, etc). However, functions that accept actual numbers typically accept int, long, short or char arguments to represent whole number…s (integer values), float or double to represent real numbers (floating point values), or complex data types that are intrinsically numeric, such as std::complex objects. (MORE)

# How do you use c plus plus in determining triangular number?

There are a number of ways you could do this. You could use the explicit formula of TriangularNumber(n) = n*(n+1)/2. You could also a for loop to sum all the numbers from 1 to n. A third way would be to use a recursive function. //first method int TriangularNumber(int n) { return n*(n+1)/2;… } //second method int TriangularNumber(int n) { int sumOfNumbers = 0; for (int i = 1; i (MORE)

# What number grade is C?

70-72% in America judging by the related link. A C in Ireland is from 55-70.

# How write program for reverse the number in c plus plus?

int RevNum( int num ) { const int base = 10; int result = 0; int remain = 0; do { remain = num % base; result *= base; result += remain; } while( num /= base); return( result ); }

# How Reverse a number in c plus plus?

int RevNum( int num ) { const int base = 10; int result = 0; do {.
result *= base;.
result += num % base;.
} while( num /= base); return( result );.

# What is programme in c plus plus of a Armstrong number?

include #include // for std::pow() unsigned int get_length(unsigned int num,const unsigned int base=10) { unsigned int len=1; while(num && (num/=base)) ++len; return( len ); } bool is_armstrong(const unsigned int num,const unsigned int base=10) { unsigned int len=get_length(num,base); unsigne…d int sum=0; unsigned int tmp=num; while(tmp) { sum+=(unsigned int)std::pow((double)(tmp%base),(double)len); tmp/=base; } return(num==sum); } int main() { std::cout (MORE)

# How do you find sum of even numbers in c plus plus?

That is an unsolvable problem, because there are an infinite number of even numbers. However, with limits, you could say... int NMax = ...; int Sum = 0; for (N=2; N

# Is C plus a good grade to get in university?

No, in general, a C indicates that the person is barely passing the material, depending on the education system, most colleges and universities count C grades as either 60s or end of 50s. It can only be a good grade if it's equivalent to 70-79%, otherwise, try harder in classes.

# How do you add n numbers by using c plus plus?

If you're reading the numbers sequentially, keep a running total. Alternatively, pass all the numbers to a function using a variable-length argument. Alternatively push the numbers into a vector then sum the vector with the following function: void sum_vector(std::vector a) { int total=0; for(int… i=0; i (MORE)

# How do you add 3 numbers using c plus plus?

int x = 1, y = 2, z = 3; int f = x + y + z;

# How do you generate two random numbers in C plus plus?

include #include #include int GetRand( int min, int max) { // Swap min and max if wrong way around. if(max

# How do you reverse a 5 digit number in c plus plus?

It doesn't matter how many digits are involved, the principal is the same. int RevNum( int num ) { const int base = 10; int result = 0; int remain = 0; do { remain = num % base; result *= base; result += remain; } while( num /= base); return( result ); }

# How do you write in c plus plus plus plus a number followed by a letter?

If you're asking how to create an identifier that begins with anumber, then the answer is you cannot. All identifiers must beginwith a letter or an underscore. If we allowed leading numbers, thecompiler wouldn't be able to distinguish whether 42 was anidentifier or a numeric value. Whereas _42 is cl…early anidentifier. (MORE)