It's a surface over which electric charges are evenly distributed, caused by the mutual repulsion between charges of the same polarity.
For conductors, the electric field perpendicular to its surface and no field exist within the conductor. As a result the equipotential lines are found near the surface. They are parallel to the surface since equipotential are perpendicular to field lines.
Arif Ullah khan utman kheel this is because for conductor E parallel is zero this means that the surface of the wave guide is at equipotential and this potential follow the laplace equation .it means that there is no maxima and minima inside the wave guide . this means that the electric field inside zero . hence the TEM do not exist in wave guide only TE and TM can be exist . if we place some conductor in the wave guide then the conductor inside will not be equipotential and the TEM waves can be exist . like in Coaxial cables
for TEM u need to a magnetic field (H) linked to an electric field .for this u need to a J relative to E (E=sigma J). because [curl H = J] but optical fiber is dielectric wave guide and sigma is zero and u only have dD/dt so there isn't H linked to E.
If this means voltage potential it is a conservative force so it is path independant, much like gravity, it doesn't matter how somthing got to where it is it will still have the same potential at that height. So if it had two different potential lines crossing it would be much like an object having different potential energies at one point in space. This is impossible.
Undesired current flow across the surface of a semiconductor device due to contamination of that surface. This disturbs the operation of the device and causes a variety of failures. Insulators can also have surface leakage current for similar reasons.
what is the geometrical shape of equipotential surface due to single isolated charge
If the field lines were not perpendicular to the surface, then they could be decomposed into components perpendicular and parallel to the surface. But if there is an E-field along the surface, the surface is no longer an equipotential.
yes
concentric spherical surfaces
As we know equipotential surface means there is no potential difference that is no work is done on surface.so lines of force must intersect surface at right angles to satisfy this statement,so that net work is zero.
0, because its equipotential surface
An equipotential surface has the same value of potential. Thus, work done would be zero. Work done = Charge X Potential difference
It's a surface over which electric charges are evenly distributed, caused by the mutual repulsion between charges of the same polarity.
For conductors, the electric field perpendicular to its surface and no field exist within the conductor. As a result the equipotential lines are found near the surface. They are parallel to the surface since equipotential are perpendicular to field lines.
Multimeter is an instrument that measures electric equipotential. Equipotential lines can be determined by connecting various points of electric potential or voltage.
Doesn't seem like they can. If they could, then that would put two different potentials along the intersection.
Equipotential lines are lines that are perpendicular to the lines representing the electric field of a particle. A particle can travel freely of equipotential lines without doing any work.