2C2H6 + 7O2 -> 4CO2 + 6H2O
By looking at the ethane I could see that I needed to put the 2 coefficient in front of it to make the oxygens come out even. Always balance O2 last in these combustion reactions.
First of all, that is not a balanced equation unless what you really meant was 2 AlCl3.
The reactants are on the left side. The coefficients are 2 and 6, so the sum is 2 + 6 = 8.
2 Al(s) + 6 HCl(aq) --> 2 AlCl3(aq) + 3 H2(g)
Oxidation (of Al) or
Displacement/substitution and reduction (of H+)
Aluminium + Hydrochloric Acid -> Aluminium Chloride + Hydrogen Gas
Al(s) + 3HCl(aq) -> AlCl3(aq) + H2(g)
Yes
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
ch3coona+FECL2
Cs2CO3 + 2HCl--->2CsCl+CO2+H2O
H+ + oh- ---> h2o
2K+2HCl-->2KCl+H2
ch3coona+FECL2
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
H2 + Cl2 --> 2HCl
Cs2CO3 + 2HCl--->2CsCl+CO2+H2O
H+ + oh- ---> h2o
2K+2HCl-->2KCl+H2
BaOH + HCl -> BaCl + H2O
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
Me too i don't know
This equation is HCl + NaOH -> NaCl + H2O.
The balanced equation for the reaction between aqueous sodium hypochlorite (NaOCl) and aqueous hydrochloric acid (HCl) is: NaOCl + HCl → NaCl + Cl2 + H2O
HCl + NaOH = H2O + NaCl is already balanced.