Nitric acid: HNO3 (acid)
Sodium hydroxide: NaOH (base)
This is therefore an acid-base reaction.
Acid + Base --> Salt + Water
Therefore: HNO3 + NaOH --> NaNO3 + H20
Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
HNO3 + H20 --> No3- + H30+
the hydrogen from the HNO3 goes to the water
Ammonium Hydroxide + Nitric acid ----> Ammonium Nitrate + Water
HNO3 + NH4OH ----> NH4NO3 + H2O
The equation is already balanced.
HNO3 -> H+ + NO3-
hope this helps~
The decomposition of nitric acid is:
4 HNO3 = 2 H2O + 4 NO2 + O2
HNO3 + NH4OH --> NH4NO3 + H2O
A reaction is not possible.
HNO3
NaNo3 Cu-4T2
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
Ba(OH)2 + 2HNO3 -------> Ba(NO3)2 +2H2O
Ca(OH)2 + 2HNO3 -> Ca(NO3)2 + 2H2O
Ammonium hydroxide and nitric acid yield ammonium nitrate and water.
Hn03 + koh > kno3 +h20
NaNo3 Cu-4T2
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
Balanced equation of nitric oxide is no3 2-
Ba(OH)2 + 2HNO3 -------> Ba(NO3)2 +2H2O
Ca(OH)2 + 2HNO3 -> Ca(NO3)2 + 2H2O
Ammonium hydroxide and nitric acid yield ammonium nitrate and water.
if you mean lead the metal: Pb + 2H+ --> Pb+2 + H2
Sodium dichromate has the chemical formula of Na2Cr2O7. The reaction with HNO3 is balanced as 2 HNO3 + Na2Cr2O7 = H2Cr2O7 + 2 NaNO3.
MgO + 2H(NO3) => Mg(NO3)2+ H2O
This is an acid - base reaction: CaO + 2H+ + ( 2NO3- ) --> Ca2+ + H2O + ( 2NO3- )
potassium hydroxide is POH and nitric acid is HNO3