The circumcenter is at (137/26, 23/26) = (5 7/26, 23/26)
The circumcenter is where the side perpendicular bisectors meet; this can be calculated by finding the equations of the perpendicular bisectors and solving the simultaneous equations that result (only 2 needs be solved, the third can be used as a check):
Let the three points of the triangle be A (2, 3), B (5, -3), C (9, 2)
The sides are AB, BC, AC with perpendicular bisectors AB', BC', AC' respectively; then:
AB has midpoint ((5+2)/2, (-3 + 3)) = (7/2, 0)
AB has gradient (-3 - 3)/(5 - 2) = -6/3 = -2
→ AB' has gradient 1/2
→ AB' has equation y - 0 = 1/2(x - 7/2) → y = 1/2(x - 7/2)
BC has midpoint ((9 + 5)/2, (2 + -3)/2) = (7, -1/2)
BC has gradient (2 - -3)/(9 - 5) = 5/4
→ BC' has gradient -4/5
→ BC' has equation y - -1/2 = -4/5(x - 7) → y = 4/5(7 - x) - 1/2
AC has midpoint ((9 + 2)/2, (2 + 3)/2) = (11/2, 5/2)
AC has gradient (2 - 3)/(9 - 2) = -1/7
→ AC' has gradient 7
→ AC' has equation y - 5/2 = 7(x - 11/2) → y = 7(x - 11/2) + 5/2
Solving for point of intersection of AB' and AC':
1/2(x - 7/2) = 7(x - 11/2) + 5/2
→ x - 7/2 = 14x - 77 + 5
→ 13x = 72 - 7/2 = 137/2
→ x = 137/26 (= 5 7/26)
Using AB'
y = 1/2(137/26 - 7/2)
→ y = 1/2(137/26 - 91/26)
→ y = 23/26
Checking using BC':
y = 4/5(7 - x) - 1/2
→ y = 4/5(7 - 137/26) - 1/2
→ y = 4/5(182/26-137/26) - 13/26
→ y = 4/5(45/26) - 13/26
→ y = 36/26 - 13/26 = 23/26 as expected.
23/53 is in its simplest form.
It's 23 to 53 .
23, 29, 31, 37, 41, 43, 47 and 53.
0.0435
180 - (107 + 53)
23/53 is in its simplest form.
53 points on 12/23/05 against the Atlanta Hawks
The GCF is 1.
875 = 53*7 and 1000 = 23*53 So, 875/1000 = 53*7 / 23*53 = 7/23 = 7/8
The sum of 16 23 and 14 is 53
It's 23 to 53 .
35 32 53 13 43 53 35 44 23 53 23
38 + 15 = 53 38 - 15 = 23
23, 29, 31, 37, 41, 43, 47 and 53.
0.0435
180 - (107 + 53)
34+53+93=180