I think this question should be read (and written) like:
"What is the electron configuration ending in 4s2 4p5 " because 4p2 4p5 is an unusual and even impossible ending of any electronconfiguration.
Answer:
Bromium, number 35, ends with ... (3d10) 4s2 4p5 (period 4, group 17)
As
Arsenic, it is group 4, and third in the p period
Ndie
calcium
The element with that electron configuration is Kr, krypton.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
Arsenic's atomic number is 33. That means neutral arsenic has 33 protons and 33 electrons. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
1s2-2s2-2p6-3s2-3p6-4s2-3d10-4p3
Arsenic has a mass number of 33 with an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3. This means that there are 3 valence electrons.
As3- = [Kr] [Kr] =1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
The element with that electron configuration is Kr, krypton.
That is Arsenic.
[Ar] 4s2 3d10 4p3
you put 3d10 after 4s2 and that is the wrong order to put it in...
Short answer: [Ar] 3d10 4s2 4p3 OR 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3
[Ar] 4s2 3d10 4p3
1s2 2s2 2p6 3s2 3d10 4s2 4p3
[Ar] 4s2 3d10 4p3 or 2, 8, 18, 5
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
Arsenic's atomic number is 33. That means neutral arsenic has 33 protons and 33 electrons. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
1s2-2s2-2p6-3s2-3p6-4s2-3d10-4p3