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The electronic configuration of Br atom is [Ar] 4s2 3d10 4p5. Since, bromide ion has gained 1- charge by acquiring one more electron, its electronic configuration is [Ar] 4s2 3d10 4p6.
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Br has 7 valence e-.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p1 is the electron configuration for Indium.
argon is because it's the last noble gas used to get to Br.. it's like a short cut, instead of writing 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^5 you can skip a lot of it …by taking th last noble gas used which is the 3p^6(Ar) and continue from there like so: [Ar] 4s^2 3d^10 4p^5
K+ and Argon Br- and krypton
The electron configuration for the Bromide anion Br- is as follows: 2s1 2s2 2p6 3s2 3p6 4s2 3d10 4p5.
Bromine has five 4p electrons.
To be neutral, Bromine (atomic symbol Br) has 35 electrons. Ions have more or less.
Br has an atomic number of 35 giving it 35 protons. Since it has a charge of 1- it will have 36 electrons to form a octet. Br- will have 35 protons and 36 electrons. The negat…ive charge indicates it gained an electron.
7 since its the 17th cloumn
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 Or 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 Or [Ar] 4s2 3d10 4p5
The electronic configuration of Br- ion is 1s22s22p63s23p64s23d104p6
Bromine is a metal element. There are 35 electrons in a single atom.
Options are not given in the question. But the following species will have the same electronic configuration as Br- ion: Neutral atom: Kr Cations: Rb+, Sr2+ Anion: Se2-