1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Rb+1 or Kr
This electron configuration is: 1s2.2s2.2p6.3s2.3p6.3d10.4s2.4p6.
VanadiumAtomic number: 23Symbol: VAtomic weight: 50.9415(1)Electron configuration: [Ar]3d34s2Group: 5BPeriod: 4
In the atom a proton has the charge +1 and the electron the charge -1.
The neutral atom with 44 electrons is ruthenium (Ru).The electron configuration of ruthenium is: [Kr]4d75s1.The number of electrons in shells is: 2, 8, 18, 15, 1.
In this context, we call an electron a beta particle.
In period 3? It has to be Boron although technically it is not a gas. The electron configuration is either 2, 3 or 1s^2, 2s^2, 2p^1 depending on what level of chemistry you are working at. If the latter looks like a different language you to, go with the first! that is actually wrong above^^, the real answer is argon so its electron configuration is 1s2, 2s2, 2p6, 3s2, 3p6
Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.
The electron configuration of Cu2+ is [Ar]3d94s0.
in the same way as sodium/potassium forms an ion. Lithium has an electron configuration of 2,1 Sodium has an electron configuration of 2,8,1, Potassium has an electron configuration of 2,8,8,1 Rubidium has an electron configuration of 2,8,8,18,1 Caesium has the electron configuration of 2,8,8,18,18,1 Notice in all cases the last number is '1'. This represents the outer most electron, shell with one electron. Since it is the outer most electron and is shielded by energy shells of electrons from the nucleus, this outer most electron is not strongly held to the atom. The atom readily releases this outermost electron , and the process is called ionisation. Chemically it is represented by the formula M(g) = M^+(g) + e^- NB 'M' is an ATOM 'M^+' is an ION (Not an atom).
what is the electron configuration for Cl 1-
Fr is in the 1st period. It removes an electron to get noble gas configuration. Fr+ does not have valence electrons.Francium has 1 electron in its outermost energy level. It donates its outermost electron to stabilize its electron configuration. Francium(I) has no valence electrons.
Fluorine's electron configuration is 1s2 2s2 2p5, and since fluoride is just fluorine with an extra electron, or F-1, its electron configuration is 1s2 2s2 2p6.
1 electron in the s orbital
the condensed electron configuration for Lu is [Xe] 6s^2 4f^14 5d^1
The electron configuration of magnesium is 1s2 2s2 2p6 3s2. Mg+ has one less electron (electrons have negative charge, so a positive charge is a lack of electrons) so you remove one from the outermost orbital: 1s2 2s2 2p6 3s1, or simply [Ne] 3s1.
Rubidium is a group 1 metal with just one valence electron. It therefore forms the ion Rb+ as it loses the electron. The ionic formula is Rb+ Cl-
1
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.