[Ar] 4s2 3d10 4p3
Arsenic [Ar]4s23d104p3
Arsenic is paramagnetic because the electron configuration is {Ar}4s^2,3d^10,4p^3. Due to the unpaired electron at the end (4p^*3*) the atom in ground state is paramagnetic. **OR Arsenic would be paramagnetic since the 4 p orbitals each contain one electron with parallel spin. These three unpaired electrons give arsenic its paramagnetic property.
abbreviated electron configuration = e.c.
Beryllium electron configuration is [He]2s2.
The electron configuration of rutherfordium is [Rn]5f14.6d2.7s2.
The electron configuration of arsenic is: [Ar]4s23d104p3.
Short answer: [Ar] 3d10 4s2 4p3 OR 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3
Iron has the electron configuration [Ar]3d64s2.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
That is Arsenic.
1s2-2s2-2p6-3s2-3p6-4s2-3d10-4p3
Arsenic's atomic number is 33. That means neutral arsenic has 33 protons and 33 electrons. Thus, its electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3.
Since arsenic is in the 4th period on the periodic table, it has 4 electron shells. Its electron configuration is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3
Arsenic has a mass number of 33 with an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3. This means that there are 3 valence electrons.
Arsenic [Ar]4s23d104p3
Neutral arsenic has 33 protons and 33 electrons. The first 33 electron orbitals are filled as 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3. The superscripts above these subshells is the number of electrons in them.
Arsenic is paramagnetic because the electron configuration is {Ar}4s^2,3d^10,4p^3. Due to the unpaired electron at the end (4p^*3*) the atom in ground state is paramagnetic. **OR Arsenic would be paramagnetic since the 4 p orbitals each contain one electron with parallel spin. These three unpaired electrons give arsenic its paramagnetic property.