Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^3 Short-hand version: [Kr] 5s^2 4d^10 5p^3 Note: The "^" symbol means the the following number is in the form of a superscript.
[Kr] 5s2 4d10
I had this same question and I figured it out. Hope I helped :)
The valences of antimony are +5, +3 and -3.
Nitrogen (N), Phosphorous (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi) all have a valence of 5, meaning they have 5 electrons in their outer shell. This means that they will readily accept three electrons, rather than lose five.
5 valence electrons.
6 Valence Electrons
Helium has two valence electrons. It is the only noble gas not to have eight valence electrons. Helium has the electronic configuration 1s2.The Noble gases have eight valence electrons in their outer shell.
Fluorine is a halogen. All halogens have 7 valence electrons. There are thus 7 valence electrons for Fluorine, 2 in the 2s orbital, and 5 in the 2p orbitals.
Sb has 5 valence electrons, In has 3, Rb has 1 valence electron and Xe has 8. So in ranking, it would be, Xe, Sb, In, Rb.
Sb (antimony)
Sb (antimony)
Antimony (Sb, # 51) has 5 valence electrons (and so do all the other elements in that group.)
Group 15 elements (N, P, As, Sb, Bi)
This would be Sb - Antimony.
N and As for two. They all have 5 valence electrons (as do Sb and Bi).
Valence electrons
the electrons in the outermost shell of an atom are considered to be the valence electrons.
Nitrogen (N), Phosphorous (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi) all have a valence of 5, meaning they have 5 electrons in their outer shell. This means that they will readily accept three electrons, rather than lose five.
Electrons in the outermost shell are valence electrons!
valence electrons