Chromium (III) has a 3+ charge.
Permanganate (MnO4-) Has a 1- charge.
Therefore it takes 3 Permanganate anions to equal the charge of a Chromium (III) cation.
This should be Cr(MnO4)3
Under condition of the strong oxidant 'perchlorate' only Cr(III) is a possible oxidation state:
so the formula of Cr(III) perchlorate is Cr(ClO4)3
Cr(MnO4)3
Mn2(CrO4)3
The formula for cobalt(III) chromate is Co2(CrO4)3.
Au2(Cro4)3
MnI3
The systematic name of this compound is Manganese(III) Sulfate(IV).
The formula for Copper (II) Chromate is CuCrO4.The copper has a 2+ charge (Cu2+) and the chromate ion has a 2- charge ( (CrO4)2-).Since the charges balance each other out, therefore, we get CuCrO4.
MnCrO4 is manganese(II) chromate
The formula for cobalt(III) chromate is Co2(CrO4)3.
Au2(Cro4)3
MnI3
The systematic name of this compound is Manganese(III) Sulfate(IV).
The formula for Copper (II) Chromate is CuCrO4.The copper has a 2+ charge (Cu2+) and the chromate ion has a 2- charge ( (CrO4)2-).Since the charges balance each other out, therefore, we get CuCrO4.
That would be chromium(II) sulfate, but really, chromium mostly exists as Cr(III) or Cr(VI), which would change the formula.
Mn2(SO4)3
MnCrO4
Manganese (II) sulfide.
The chemical formula MnBr2 is for manganese bromide.
first of all chromate and cloride are DIFFERENT. that being said, Fe2(CrO4)3