Height of flag pole: tangent(48.4) times 7.42 = 8.36 yards rounded to two decimal places
Approx 8.36 yards.
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
If the angle of elevation is 32 degrees then using the tangent ratio in trigonometry the height of the tree is 18.75 feet rounded up to two decimal places
tan(A) = 120/100 =39.81 degrees
51.34019175 degrees or as 51o20'24.69''
It is tan-1(170/200) = 40.365 degrees to 3 decimal places
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
The flagpole is 15.92 metres, approx.
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
18.6 m/52.6 degrees tan= 14.2
If you also know its shadow then you can work out the angle of elevation
By means of trigonometry if you know the angle of elevation or by comparing it with a nearby object if you know its height and shadow length.
Using trigonometery if you know the length of its shadow and angle of elevation
Using the tangent ratio height of telegraph pole is 55 feet to the nearest integer.
It is: tan(52)*9 = 11.519 meters rounded to three decimal places
tan(36) = H/58 where H is the height of the tower. So H = 58*tan(36) = 42 feet.
A pole casting a shadow 49 feet long with an angle of elevation of the sun of 44.8 degrees is 50 feet tall. (47.98 rounded to two places)Tangent (theta) = opposite / adjacentTangent (44.9) = X / 49X = 47.98This does not take into account the curvature of the earth, but the error in this example is inconsequential, specifically an elevation error of about 0.015 percent.