The inductive reactance of a 15 Henry inductor at 60 Hz is about 5.7 KOhms. (2 pi f l)
2 * (60*2*pi) = 754 ohms
5,652V
Inductive reactence is given by Xl = 2*pi*F*L = 2*3.14*60*9 = 3.912 K Ohm
While it is true that an inductor opposes the flow of an alternating current, it does not necessarily 'block it'. The quantity that opposes the flow of an AC current is the inductor's inductive reactance, expressed in ohms. Inductive reactance is proportional to the frequency of the supply voltage and, at 50 or 60 Hz, the reactance of a transformer's winding is relatively low (although very much higher than its resistance) and, while this acts to limit the amount of current flow, it certainly doesn't act to block that flow.
The capacitive reactance of a 1 µF capacitor at a frequency of 60 Hz is about 2700 ohms.
50 Hz has an edge over 60 Hz as it will have less skin effect and therefore line resistance will be less. Therefore, voltage drop as well as unwanted loss of energy in the line will be less. That means dip in supply voltage at user end will be less and efficiency will be more.AnswerThe difference in 'AC resistance' due to the effect of skin effect between 50/60 Hz is insignificant, just as the increase in inductive reactance, or the decrease in capacitive reactance is insignificant.The answer to your question is that the two frequencies simply resulted from the independent development of electricity distribution networks in different parts of the world, and there is no inherent advantage of one frequency of the other.Transformers for 60 Hz are smaller than for 50 Hz, assuming a given power rating. That is because the iron magnetic core can be reduced in size by 20% for 60 Hz, for the same peak magnetic flux density.
If the load is non inductive and straight resistive then there is no problem. Inductive loads like motors, a 60 Hz device can be used on 50 Hz but it is much harder on the equipment if 50 Hz is used on a 60 Hz system.
Inductive reactence is given by Xl = 2*pi*F*L = 2*3.14*60*9 = 3.912 K Ohm
While it is true that an inductor opposes the flow of an alternating current, it does not necessarily 'block it'. The quantity that opposes the flow of an AC current is the inductor's inductive reactance, expressed in ohms. Inductive reactance is proportional to the frequency of the supply voltage and, at 50 or 60 Hz, the reactance of a transformer's winding is relatively low (although very much higher than its resistance) and, while this acts to limit the amount of current flow, it certainly doesn't act to block that flow.
inductive reactance= XL= 2*pi*.1*60=12pi ohm
While it is true that an inductor opposes the flow of an alternating current, it does not necessarily 'block it'. The quantity that opposes the flow of an AC current is the inductor's inductive reactance, expressed in ohms. Inductive reactance is proportional to the frequency of the supply voltage and, at 50 or 60 Hz, the reactance of a transformer's winding is relatively low (although very much higher than its resistance) and, while this acts to limit the amount of current flow, it certainly doesn't act to block that flow.
XL= 2 * Pi * f * L = 6.28 * 60 * .5 = 188 ohms
You need to divide the supply voltage by the impedance of the load. The impedance of the load is the vectorial sum of its resistance and reactance, where reactance is proportional to frequency.
Your question is rather vague, but what you may be asking is, "What happens in a circuit if the supply frequency is increased?"Well, circuits have some degree of natural resistance, inductance, and capacitance, which may be modified with resistors, inductors, and capacitors. Frequency affects each of these, as follows:Resistance -Resistance is inversely-proportional to a conductor's cross-sectional area. In a DC circuit, charge flow distributes itself across the full cross section of the conductor. However, with AC currents, an effect called 'skin effect' comes into play -this describes the tendency of charge carriers to move closer to the surface of the conductor, essentially reducing the effective cross-sectional area of the conductor, and increasing its resistance. We call this the 'AC resistance' of the conductor; at normal supply frequencies (50/60 Hz) this is insignificant, however it increases significantly with frequency.Inductance -Inductive reactance opposes the flow of AC current, and is directly proportional to the circuit's inductance and to the frequency of the supply. So, as frequency increases, the circuit's inductive reactance increases.Capacitance -Capacitive reactance opposes the flow of AC current, and is inversely proportional to the circuit's capacitance and to the frequency of the supply. So, as the frequency increases, the circuit's capacitive reactance falls.
It will work ok. The iron's heating element is predominately resistive in order to produce heat. If the heating element is coiled, it will have a small inductive reactance which acts similar to a resistance to current flow but does not contribute to heating. At a higher a.c. frequency (60 Hz instead of 50 Hz) it will have a slightly higher inductive reactance and, therefore, a slight reduction in heat production.
The current through a pure, or ideal, inductor having zero resistance, would lag the voltage with a phase angle of 90 degrees. The inductive reactance of a 1 Henry inductor at 60 hz is about 380 ohms. XL = 2 * pi * f * L so 200 volts at 380 ohms is about 0.53 amps and the power drawn, using the basic Power equation: power = volts * amps, would be about 105 vars. Var is the correct term for volts times amps, or volt-amp-reactive, where we consider the phase angle to be 90 degrees.
The total DC resistance is (33+47) = 80 ohms.The total reactance is j(60+30) = j90 ohms.The total impedance of the string is [ 80 + j90 ] ohms,= 120.4 ohms at a phase angle of 48.37 degrees (both numbers rounded).
The capacitive reactance of a 1 µF capacitor at a frequency of 60 Hz is about 2700 ohms.
x/r ratio is reactance/resistance where reactance is impedance * frequency (60 hz)