The molar mass of H2O =
(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O
1 mole of H2O = 18.0152g H2O
1 mole of H2O molecules = 6.022 x 1023 molecules H2O
Convert molecules to moles.
5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =
8.31 x 10-22 mole H2O
Convert moles to grams.
8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2O
Answer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O
The mass is 49,06 g.
The mass of ammonia is 339,7 g.
45mL of plain water has a mass of about 45 grams.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams.417 grams H2O / (18.0 grams) = .0232 moles H2O
7.50x10^20 molecules x 1 mol/6.02x10^23 molecules x 194 g/mole = 0.242 grams
The mass is 74,7 mg.
im sorry its 10 to the 21 power
Avogadro's Number is defined as the number of molecules in one gram atomic molecular mass of a substance and is known to have the approximate value of 6.022 X 1023. The gram molecular mass of water, with formula H2O, is 18.01528. Therefore, the number of water molecules in 1.805 grams of water is: (1.805/18.01528)(6.022)(1023) or 6.034 X 1022 molecules, to the justified number of significant digits.
The mass is 49,06 g.
The mass is 483,62 g.
The formula of water is H2O and that of oxygen molecules is O2. The fraction by mass of oxygen in water is the atomic mass of oxygen divided by the molecular mass of water, which in turn is the sum of the atomic mass of oxygen and twice the atomic mass of hydrogen, or {15.999/[15.999 + 2(1.008)]} = 0.888, to sufficient significant digits to correspond to the problem information of 52.8 grams of water. The mass of oxygen in this amount of water therefore is 0.888 X 52.8 = 46.9 grams. The molecular mass of oxygen atoms is 2 X 15.999 = 32.0, so that 46.9 grams corresponds to 46.9/32.0 = 1.466 moles of oxygen molecules. The number of molecules per mole of any substance is Avogadro's number, 6.022 X 1023. The answer to the problem is this number multiplied by the number of moles = 1.466 X 6.022 X 1023 = 8.83 X 1023.
The answer is 50,196 g.
The mass of ammonia is 339,7 g.
45mL of plain water has a mass of about 45 grams.
15.994 grams/mol, but it can rounded to 15.99 or 16.0 g/mol.
The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.
25 grams of steam are in 25 grams of water.