One liter of ozone gas at 1 atmosphere and 0°C has the mass of is 2.141 gm. At 20°C (STP) that would be 1.995 gm. 3.36 L would be 6.70 gm (to three sig figs).
3.21*(16.0*3) = 154 grams O3
The answer is 0,9.10e+23 molecules.
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
To determine how many atoms are present in 56 liters of oxygen gas at STP you first need to know that there are two atoms in a single molecule. Then, you would work the scientific formula to determine the number of molecules in the oxygen gas.
0.3
To find it's density
Mass of Hydrogen gas:- 2g/mol Mass of Oxygen gas :- 32g/mol Therefore, Oxygen gas is more heavier
At STP it is a gas
A gas at STP.
part of the oxygen group....gas, nonmetal...
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.
3.058
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
nitros oxide N2O
atoms have a higher mass than molecules. Because both gases at STP have the same number of molecules per unit volume, the gas must be denser.
To determine how many atoms are present in 56 liters of oxygen gas at STP you first need to know that there are two atoms in a single molecule. Then, you would work the scientific formula to determine the number of molecules in the oxygen gas.
0.3
Gas