0
The Mr of Carbon monoxide (CO) is 28, since Ar of Carbon is 12 and Ar of Oxygen is 16. Then proportion by mass will be simple ratio of 12 to 16 giving 3:4
Wiki User
∙ 13y ago
Wiki User
∙ 13y ago1/2
Add your answer:
Earn +20 pts
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
What is the mole ratio of salt to water in Co(NO3)2.6H2O?
2:1
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
How does the experimental mole ratio compare with the theoretical mole ratio?
the experimental mole ratio has a bigger penis
How many liters of Hydrogen gas are formed from the complete reaction of 1.07 moles of carbon. C h20--- CO H2?
You stated the amount of carbon you had, but how much water (separated into its constituents by electrolysis, otherwise if you dump water on carbon you wind up with nothing more than wet carbon) is available? Let's assume you've got an excess of it and go from there.In a real-life situation you won't get any hydrogen gas. In order of reactivity are hydrogen, oxygen and carbon. One of three things will happen here.The most likely reaction is that the hydrogen and oxygen will recombine into water and, once again, you've got wet carbon...that is, unless the heat from the very exothermic 2H2 + O2 -> 2H2O reaction sets the carbon on fire, in which case it'll scavenge atmospheric O2 and you'll receive some CO2, some CO and a little free carbon, aka "soot."Under different circumstances, you might get some CH4 and some O2. And because you have 1.07 moles C, you'll wind up with 1.07 moles methane - giving you 23.968 liters of methane at STP.If you have a really nice lab that can emulate photosynthesis, you could convert the three elements into glucose. That's not too likely; you will probably wind up with the same block of carbon and glass of water that you started out with.The chemical reaction should be written as shown below : C + H2O -----> CO + H2 The balanced chemical reaction equation indicates that 1.0 mole of H2 gas is produced for each mole of carbon that reacts. Therefore you have : n H2 = (1.07 mole C ) ( 1.0 mole H2 / 1.0 mole C ) = 1.07 moles H2 At STP, there are 22.7 L per mole of ideal gas. Therefore the H2 liters at STP is given by : V H2 at STP = ( 22.7 L at STP / mole ideal gas ) ( 1.07 moles H2 ) V H2 at STP = 24.3 L of H2 at STP
How many moles of H2 are required to react with 5.0 moles O 2?
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
What is the mole ratio of C5H12 to H2 in the following reaction?
c5h12toh2
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 19.1 moles of water vapor?
CO2 + H2 <-> CO + H2O all one to one ( I assume that 99.1 is grams. Always units!!!! ) 99.1 grams H2O (1 mole H2O/18.016 grams)(1 mole H2/1 mole H2O) = 5.50 moles of hydrogen gas needed If that was 99.1 moles water vapor then it would take 99.1 moles hydrogen gas at a one to one ratio.
What is the mole ratio of salt to water in Co(NO3)2.6H2O?
2:1
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
How does the experimental mole ratio compare with the theoretical mole ratio?
the experimental mole ratio has a bigger penis
How many atoms in 1g H2?
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
What is the percent yield of h2o if 58g h2o are produced by combining 60g o2 and 7g h2?
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Give the mole ratio for the following equation Zn 2HCl -- ZnCl2 H2?
The reaction is:Cl2 + H2 = 2 HClThe moles rato is 1:1.
Calculate the number of mole of hydrogen in 37.66gm?
37.66 (g H2) / 2.016 (g/mol H2)= 18.68 mole H2Molar mass of hydrogen: 2.016 (g/mol H2)
How many liters of Hydrogen gas are formed from the complete reaction of 1.07 moles of carbon. C h20--- CO H2?
You stated the amount of carbon you had, but how much water (separated into its constituents by electrolysis, otherwise if you dump water on carbon you wind up with nothing more than wet carbon) is available? Let's assume you've got an excess of it and go from there.In a real-life situation you won't get any hydrogen gas. In order of reactivity are hydrogen, oxygen and carbon. One of three things will happen here.The most likely reaction is that the hydrogen and oxygen will recombine into water and, once again, you've got wet carbon...that is, unless the heat from the very exothermic 2H2 + O2 -> 2H2O reaction sets the carbon on fire, in which case it'll scavenge atmospheric O2 and you'll receive some CO2, some CO and a little free carbon, aka "soot."Under different circumstances, you might get some CH4 and some O2. And because you have 1.07 moles C, you'll wind up with 1.07 moles methane - giving you 23.968 liters of methane at STP.If you have a really nice lab that can emulate photosynthesis, you could convert the three elements into glucose. That's not too likely; you will probably wind up with the same block of carbon and glass of water that you started out with.The chemical reaction should be written as shown below : C + H2O -----> CO + H2 The balanced chemical reaction equation indicates that 1.0 mole of H2 gas is produced for each mole of carbon that reacts. Therefore you have : n H2 = (1.07 mole C ) ( 1.0 mole H2 / 1.0 mole C ) = 1.07 moles H2 At STP, there are 22.7 L per mole of ideal gas. Therefore the H2 liters at STP is given by : V H2 at STP = ( 22.7 L at STP / mole ideal gas ) ( 1.07 moles H2 ) V H2 at STP = 24.3 L of H2 at STP
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor?
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
