H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)
Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
2Na(S) + 2H2O(l) --> 2Na+(aq) + 2OH-(aq) + H2(g)
The net ionic equation for naoh plus ch3cooh to ch3coona is as follows: CH3COOH + OH- ==> CH3COO- + H2O
OH(-)+CH3COOH-->CH3COO(-)+H2O
It is Balanced
NaOH
Na+ + C2H3O2
OH- + H+ H2O
Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
(2 Na+ + HS- + OH-)(aq) + 2 (Ag+ + [NO3]-)(aq) ---------- Ag2S(S) + 2 (Na+ + [NO3]-)(aq) + H2O
sodium acetate = Na+C2H3O2- (a salt) nitric acid = HNO3 equation: NaC2H3O2 + HNO3 --> NaNO3 + C2H4O2
Sodium acetate gets dissociated and solvated in water. CH3COONa + H2O = CH3COO-(aq) + Na+(aq)
The products are sodium chloride, which remains dissolved, and water. The complete ionic equation is Na+ + OH- + H+ + Cl- --> Na+ + Cl- + H2O The net ionic equation is: H+ + OH- --> H2O
OH- + H+ H2O
NaCN + H2O ---> CN-+ H3O++ Na+ In that equation Na+ is just a spectator ion,, further reaction with water results in: CN- + H2O ---> HCN + OH- thus causing the resulting equation to be basic
ClO4-1 + Na+1 + H+1 + OH-1 = NaClO4 +H2O.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
The net ionic equation is Ag+(aq) + I- --> AgI(s) The sodium (Na+) and nitrate (NO3-) are spectators as always.
NaOH(aq) + HCl(aq) ---> H2O(l) + NaCl(aq) Na+ + OH- + H+ + Cl- ---> H2O + Na+ + Cl-
Balanced Molecular Equation:HNO2(aq) + NaOH(aq) NaNO2(aq) + H2O(l)Complete Ionic Equation: HNO2 (aq) + Na+ (aq) + OH- (aq)Na+ (aq) + NO2- (aq) + H2O (l)Net Ionic Equation: HNO2 (aq) + OH- (aq)NO2- (aq) + H2O (l)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
(2 Na+ + HS- + OH-)(aq) + 2 (Ag+ + [NO3]-)(aq) ---------- Ag2S(S) + 2 (Na+ + [NO3]-)(aq) + H2O