In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
By converting the mass into the number of moles (moles = mass(g)/molecular weight) and then multiplying by avogadro's number you get an answer of 6.842 x 1022 atoms.
0.500 grams CO2 (1mol/44.01g )(1mol C/1mol CO2 )(6.022 X 10^23/1mol C )
= 6.84 X 10^21 atoms of carbon
Hai
1.3 mol
48,177 134 32.1023 atoms
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
There are approx 6.02 X 1024 oxygen atoms. --> 5mol CO2 (2mol O2/ 1mol CO2)= 10 mol O2 Then Avagadro's number is used to calculate the number of atoms.... 10 mol O2 (6.02 X 1023/ 1mol) = 6.02 X 1024
6.022 x 1023
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
(90 g CO2 / (12.0+2*16.0) g/mol CO2) = 2.05 mol CO2 = 2.05 mol C2.05 mol C * 12.0 g/mol C = 24.5 g C
2.65 mol * 64.07 g/mol = 169.79 g
There are 1.204 x 1023 atoms in .200 mol of Pb.
1.3 mole C2H2 will produce 2.6 mole CO2, weighting 2.6(mol) x 44 (g/mol) = 114 g CO2
my Glizzy
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000