Number of moles are calculated using the equation n=m/M
where n is the number of moles, m is the mass of the substance and M is the molar mass of the substance.
Molar mass of water = 18 g mol-1
Number of moles of water = 3.8 g /18 g mol-1
= 0.21 mol
Number of moles of H in H2O =2
(the subscript next to the chemical symbol of an element indicates the number of moles of that element in that molecule)
Number of moles of H in 3.8 g of H2O = 2 x 0.21 mol
= 0.42 mol
How many moles of water are in 3.6 grams of water? 2 mol of hydrogen plus 1 mol of oxygen will result in 1 mol of water; so 2 H atom gram-mol (2g) + 1 O atom gram-mol (aprox 16g) = aprox 18 grams; or 1 H2O mol = aprox 18g; so 3.6g = aprox 0.2 H2O mol (3.6/18)
Number of moles : mass / mass per mole : 3.8 / (1*2)+16
: 3.8 / 18
: 0.2375
Moles = Mass(g)/Mr
Mr of H2O = (1 x 2) + (1 x 16) = 18
Moles = 3.7 / 18 = 0.206 moles(3 sig.)
OR
37/180 moles (fraction)
There are 2 moles of water in 36grams.
Reason explaining why:
36g H20 multiplied by the molar mass (which is 1mol/ 18gH20) equals 2molesH20.
1 mole = 18 g.
so 3.2 mole = 57.6 g of water.
Mass ÷ Molar mass = moles
3.00 grams ÷ 18.0 = 0.167 moles H2O
3.6 x (6.022x10^23)
3.6/18 = 0.2 moles water.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
0.515 moles
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The answer is o,5 mol.
moles of what?
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
0.515 moles
You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
There are 0.003659 N2O moles. So there are o.007318 moles of N.
consider two moles of HCHO as 2HCHO = 2CO & H2 here O has oxidation no = -2 & so C shall have oxidation no = +2
1 mole of sulfuric acid=98g(?)chemical formula of sulfuric acid=H2SO4Atomic mass of Hydrogen(H)=1Atomic mass of Sulpher(S)=32Atomic mass of Oxygen(O)=16(1)2+32+(16)4=2+32+64=98uTo calculate number of molesNo. of moles=given mass/atomic massno. of moles=49/98no. of moles is 0.5g
The answer is o,5 moles MgO.