pH = -log(hydronium concentration) [Hydronium is H3O.
-log(1 x 10-9) = 9
.5M
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
Definition to use for the log (logarithm):the logarithm of a number (n) to a given base (b) is the exponent (e) to which the base must be raised in order to produce that number.(Raising to the power is the inverse of taking the logarithm.)logb(n) = e or be = nFor example, the logarithm of 1000 to base 10 is 3 ( log10(1000) = 3),because 10 to the power of 3 is 1000: 103 = 1000.-log10[H+] is (by definition) used to calculate the pH of a dilute solution in which [H+] = concentration of H+ (or H3O+) in mol/L.pH = -log10[H+] or [H+] = 10-pH
1.39
-log(1.5*10-11) = 9.8pH
p = -log[H+] = 12.4
Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]
True
In an aqueous solution, the concentration of H3O+ is the same as the concentration of H+. If you know the pH of the solution, then that's equal to 10^(-pH).
13.7 take the negative logarithm
13.7
If the PH of lemon juice at 298 k is found to be 2.32, the concentration of H3O plus ions in the solution would be 0.5 M.
.5M
A basic solution has more OH- ions A solution with more H3O+ is acidic.
The H3O+ concentration in a solution with pH 3.22 = 1x10^-3.22 M or 6.03x10^-4 M.If a solution is 100 times less acidic, then the H3O+ concentration will be 6.03x10^-6 M.Put another way, 100 times less acidic will have a pH of 5.22 and H3O+ = 1x10^-5.22 = 6.03x10^-6M