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What is the probability that if 9 letters are typed no letters are repeated?
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What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has three numerals followed by two letters followed by three numerals?
This is one minus the probability of having no repeated letters. The probability of having no repeated numbers is 10/10 x 9/10 x 8/10 x 7/10 x 6/10 x 5/10 which equals 0.1512. The probability of having no repeated letters is 26/26 x 25/26 = 0.96153846153846153846153846153846 These multiplied together gives 0.14538461538461538461538461538462 1 minus this is 0.85461538461538461538461538461538 And so the probability of having a repeater letter or digit is roughly 0.855
How many different ways can you arrange the letters of the word chocolate?
chocolate = 9 letters, where o and c are repeated 2 times. There are 9!/(2!2!) = 90,720 ways.
How many permutations are there for the letters in the word telephone?
The number of combinations of the letters TELEPHONE is 9 factorial, or 362,880. From that, however, we have to divide by 4 to account for the E being repeated twice, so the number of distinct combinations is 90,720.
A bag contains 26 letters and 9 numerals. Aubrey draws two cards from the bag. What is the probability that she draws 2 numerals?
The answer is 9/149.
How many ways can you rearrange the letters in POSSESSES?
9! (nine factorial)However, since the S is repeated 4 times you need to divide that by 16, and since the E is repeated once, you need to divide that by 2. The final result, which is the number of distinctcombinations of the letters POSSESSES is 11340.
What is the number of distinguishable permutations of the letters in the word EFFECTIVE?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. Since the letter E is repeated twice we need to divide that by 4, to get 90,720. Since the letter F is repeated once we need to divide that by 2, to get 45,360.
How many ways are there to rearrange the letters in inaneness?
The number of permutations of the letters of the word depends upon the number of letters in the word and the number of repeated letters. Since there are nine letters, if there were no repetitions, the number of ways to rearrange these letters would be 9! or 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1. But don't do the multiplication just yet. To account for the repeated letters, we need to divide by 3! (for the 3 Ns) by 2! (for the 2Es) and by another 2! (for the 2 Ss). This gives a final answer of 15,120 permutations of these letters.
How many permutations of the letters in the word Louisiana are there?
The number of permutations of the letters in the word LOUISIANA is 9 factorial or 362,880. However, since the letters I and A are each repeated once, you need to divide that by 4 to determine the number of distinct permutations, giving you 90,720.
What is probability of throwing 9 heads in a row?
If you toss a coin often enough the probability is 1. The probability of 9 H in the first 9 tosses is (1/2)9 = 1/512
What is the probability of rolling a sum of 9 with two die?
The probability is 4/36 = 1/9
What A valid password on a website contains 3 letters A-Z 26 total followed by 3 digits 0-9 Letters and numbers can be repeated The number of possible passwords equals?
263 X 103 = 17576000
Would License plates in toontown consist of three letters followed by a digit from 1 to 9 and if so how many different license plates are possible?
Any three letters, in any order, including repeated letters gives 263 combinations each of which could have one of 9 digits so 26 x 26 x 26 x 9 ie 158184 different plates.
