Google Ohms Law. It will give you all the formulas you need to compute Ohms,Volts and Amps. Simple formulas :-)
The resistance of a circuit if current flow is 6 amperes and voltage drop is 120 volts is 20 ohms. (Ohm's law: resistance is voltage divided by current.)
20, now go study.
6
8
6
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
V = i*r v = 2 * 60 v= 120v
By Ohm's law, resistance is voltage divided by current, so the resistance of a light bulb can be measured by observing the voltage across it simultaneously with observing the current through it. Interestingly, the hot resistance is significantly different that the cold resistance, so measuring resistance with an ohmmeter will not give a meaningful resistance. This is because the resistance of a light bulb has a positive temperature coefficient. Take a typical 60 W 120V light bulb, for instance... Its cold resistance is about 16 Ohms. Calculate current and power at 120 V and you get 7.5 A and 900 W. The truth is that at 60 W, the bulb pulls 0.5 A and has a resistance of 240 Ohms.
Here is my full question - A typical 120-volt household circuit delivers 350 watts of power to an appliance, and another 10 watts of power are consumed by the circuit. There is no ground fault. a. How much current is carried by the hot wire? b. How much current is carried by the neutral? c. How much current is carried by the grounding conductor? d. Calculate the resistance of the circuit: by "consumed by the circuit" I assume you mean consumed by the wires. Assuming resistive loads only, the total load is 360 watts, thus the current is 3 amps. The current flows in the hot and the neutral.
12
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
Ohms law states that E=I * R, or voltage equals current times resistance. Therefore current equals voltage divided by resistance. 120v divided by 16 ohms equals 7.5 amps.
"Volts" is electrical pressure applied to a circuit; whereas, "ohms" is electrical resistance to that pressure. One cannot determine ohms from voltage without knowing either the current (in "amps") or power (in "watts"). A normal 120V household circuit can handle a maximum of 20 amps, so using ohm's law of resistance = voltage / current, the minimum resistance required in a 120V household circuit would be 6 ohms. Any less than 6 ohms will cause the circuit breaker to trip.
A circuit breaker is designed to "trip" when more than its rated current passes through the breaker. The current is caused by the 120V across a load of a certain resistance. The wire conducting the current must be sized to the current. For 15 amps you need 14 gauge wire. The breaker will be labeled and will have a current and voltage rating printed on the breaker.
You are mad idiots fools
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
The formula you are looking for is V = IR where V = Voltage I = Current R = Resistance With some formula manipulation and numbers plugged in you get I = 120V / 9.6Ω I = 12.5A The kettle would have 12.5 volts of current running through it.
Power is measured in Watts, power (Watts) = E (volts) x I (current - amps) current is determined by the internal resistance (R) of the lightbulb, the lower the resistance the more current will flow. 120v x 0.5a = 60W 120V x 0.83a = 100W the 100W lightbulb will draw more current We also have Ohm's law: E(volts) = I (amps) x R (ohms) Household voltage stays the same at 120v we have for a 100w lamp: 120v = I x R R = 120v/0.83 amps R = 144.6 ohms for a 60w lamp: 120v = I x R R = 120v/0.5 amps R = 240 ohms The higher watt lamp has lower resistance.
You have to replace the wire (as you are increasing the current capacity), the outlet, and the breaker. Essentially you have to remove the old circuit and put in a new one. You can't reuse parts of the old circuit as you are increasing the current capacity and they would be underrated.
The circuit will have zero amps. There is one value missing from the question. The equation that you are looking for is I = E/R. Amps = Volts/Resistance or I = W/E or I = Sq Root of W/R.Once you find the resistance or watts, using the equations above you can find the amperage the circuit draws.
ohms = volts/amperes 6 ohms = 120 volts / 20 amperes