Could it be.... 20 ohms(?)
35 ohms
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
5 ohms
5 ohms
When a resistor is in series. Total resistance =R1+T2+R3. Therefore 20+8+4=32 The total resistance is 32 ohms.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
5 ohms.
5 ohms
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).