Your service provider will give you that information The size will depend on: A) how close to the transformer are you. B) copper or aluminum C) Yes, you have a 400amp service but what will your actual peak amp usage be. D) Underground or overhead.
You need to refer to the wiring regulations that apply in your country.
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Answer for USA, Canada and countries running a 60 Hz supply service.
A 3/0 copper conductor with an insulation factor of 90 degrees C is rated at 210 amps. Because the wire is a motor feeder the electrical code requires it to be sized at 125% of the motors full load amperage. 210 x 125% = 263 amps. A 250 MCM copper conductor with an insulation factor of 90 degrees C is rated at 265 amps.
For a 5% volt drop of 11.5 volts the total resistance should be 11.5 / 200 ohms, or 11.5 (200 x 900) ohms per ft for a twin cable, which is 0.000064 ohms per ft. The cable size is 3/0 (US) or 80 sq-mm (Europe).
Direct burial wire or cable set is governed on the insulation thickness. Direct burial of wire or cable, to code, must have two inches of sand above and below the wire or cable set. A marker warning tape must be placed one foot below grade, above where the wire or cable set is buried. There are three types of cable sets for direct burial, ACWU, NMWU and Teck cable.Now to answer the question, this is a voltage drop question.
A 4/0 copper conductor or a 300 MCM aluminium conductor will limit the voltage drop to 5% or less when supplying 200 amps for 450 feet on a 240 volt system.
A 3/0 copper conductor will limit the voltage drop to 3% or less when supplying 200 amps for 450 feet on a 480 volt system.
Parallel 1000 MCM copper conductor will limit the voltage drop to 3% or less when supplying 600 amps for 450 feet on a 240 volt three phase system.
#10 wire.
8 gauge will be sufficient with less than a half volt drop
To answer this question the voltage and load amperage is needed.
Assuming being fed by c32 breaker for start load minimum cable size SWA is 70mm which will go to 456 meters
The formula you are looking for is I = W/E.
The main piece of information needed is the load wattage or amperage that will be connected to the power supply. Once this is known the power supply of a greater size that the load should be chosen. Also with this information the size of the wires can be calculated from the power supply to the load. Too small a wire will create a voltage drop at the load end of the circuit. This will cause under performance of the load.
16 mm to 18 mm
8 gauge will be sufficient with less than a half volt drop
To answer this question the voltage and load amperage is needed.
Ohms law says that watts are equal to volts times amps. 240v X 13.5a = 3240 va VA / 1000 = Kva So, your load requires 3.24 Kva. The transformer should have a rating greater than this as a safety factor, so you would choose the next larger size, in this case probably a 5 Kva transformer with a 480v primary and a 240v secondary. Your local electrical codes may require a larger safety factor, so you would want to consult them before buying the transformer!
The size of the generator is based on the size of the load you want to supply. Size up the load in watts or amps along with what phase (single or three) and voltage that the load requires. These are needed to give a complete answer.
Assuming being fed by c32 breaker for start load minimum cable size SWA is 70mm which will go to 456 meters
The number of pulleys needed to lift a load varies based on the size of the load. A very small load can be lifted with just one pulley while large loads may require many pulleys to adequately lift the load.
The formula you are looking for is I = W/E.
The main piece of information needed is the load wattage or amperage that will be connected to the power supply. Once this is known the power supply of a greater size that the load should be chosen. Also with this information the size of the wires can be calculated from the power supply to the load. Too small a wire will create a voltage drop at the load end of the circuit. This will cause under performance of the load.
That question cannot be answered without knowing the load on the beam.
A DLH will work.
38 feet longIt is not possible to give a definite answer without more detail. The construction and type of roof will determine the load (weight) bearing on the beam, and factors such as wind load and earthquake load, and the way the roof bears on the beam (truss/point load/distributed load) will all affect the sizing.