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What three consecutive numbers total 135?

Updated: 8/17/2019
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15y ago

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44,45,46

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15y ago
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Q: What three consecutive numbers total 135?
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Three consecutive numbers have a sum of 135 what are the numbers?

44 + 45 + 46 = 135


Three consecutive numbers have the sum of 135 what are the numbers?

44 + 45 + 46 = 135


Three consecutive numbers have a sum of 135?

44,45,46


What Three consecutive numbers total 135 what are the numbers?

let the three consecutive no.s be k-1,k and k+1,where k is a positive whole no. so (k-1)+k+(k+1)=135 according to the question or, 3k=135 or, k=45 which gives the no.s as 44,45,46 44+45+46=135


What are 2 consecutive numbers that that add up to 271?

The numbers are 135 and 136.


What are two consecutive whole numbers that 134.2 lies between?

134 and 135


What are 2 consecutive numbers that add up to be 135?

137


What are 3 consecetive numbers that add up to 135 and how do you get it?

138


Find three consecutive odd integers whose sum is 135?

Those three odd integers are 43, 45, and 47.


Three consecutive integers whose sum is 135?

Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.


The sum of three consecutive integers is 135 What is the greatest of the three integers?

Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.


What are three consecutive odd integers whose sum is 135?

43+45+47=135. i had this question for my online math class. but i don't know how to make that into an equation. something like 3x+2...maybe.. here is how you do it: We need three consecutive odd integers so we will let the first one be x, the next is x+2 and then third is x+4 3x+6=135 3x=129 x-43 x+2=45 x+4=47 So the three numbers are 43, 45 and 47