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Actually resistance is directly proportional to the length provided area remains constant. But as we stretch the wire only its volume would remain constant. So its area is to be decreased as length increases. V = pi r^2 * L

Now we have R = K * L / pi r^2

Multiplying numerator and denominator by L we get R = K/V * L^2

So resistance is found to be proportional to square of length

Hence as length gets increased by 2 times, its resistance value would increase by 4 times.

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Q: What will happen to the resistance of a wire if it is stretched to increase its length by 2 times?
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