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In serial communication disconnection and continuing how start bit and stop bit recorganized by the receiving device for correct framing?
Answer The start bit in serial communication is opposite polarity puls than the stop bit depending on the system the start bit for instance is a positive puls (hi…gh) and the stop bit will be a negative puls (low)
A bit is a single digit of a binary number.
Frames of 1000 bits are sent over a 1-Mbps channel using a geostationary satellite whose propagation time from the earth is 270 msec Acknowledgements are always piggybacked onto data frames The head?
Let t=0 denote the start of transmission.At t=1 msec,the first frame has been fully transmitted.At t=271 msec,the first frame has fully arrived.At t=272 msec,the frame … acknowledging the first one has been fully sent.At t=542 msec,the acknowledgement-bearing frame has fully arrived.Thus, the cycle is 542 msec.A total of k frames are sent in 542 msec,for an efficiency of k/542.Hence (a)k=1,efficiency=1/542=0.18% (b)k=7,efficiency=7/542=1.29% (c)k=4,efficiency=4/542=0.74%
What type of construction is it when the internal body structure of a vehicle is used as its frame a Unibody b Body-frame c Integral or d Body-over-frame?
1 A 16 bit monosample is used for digitization of voice If 8 kHz is the sampling rate then the rate at which bit is transferred is?
may be 128
Consider a logical address space with 4 pages of 1024 bytes per pageeach mapped onto a physical memory of 64 frames. how many bits are there in logical address?
4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2+10=12 bits Physical memory = 10 +6 =16 bits
How many bits are in logical addresss. If a logical address space of eight pages of 1024 words each mapped onto a physical memory of 32 frames?
a. Logical address will have 3 bits to specify the page number (for 8 pages) . 10 bits to specify the offset into each page (210 =1024 words) = 13 bits. … b. For (25) 11 32 frames of 1024 words each (Page size = Frame size) We have 5 + 10 = 15 bits.
Most modern operating systems are either 32 bit or 64 bit but it mostly has to do with memory coding. 32bit can utilize a maximum or 4gb or RAM due to the amount of nu…mbers it uses to identify a location on the RAM (32 numbers). 64 bit can use far more memory (over 128gb) while 16 bit can use far less (not sure of exact numbers) Anything you buy today should be at least 32bit if not 64 bit
32 bits. which is 4 bytes (8 bits in each byte).
Consider a logical address space of eight pages of 1024words each mapped onto a physical memory of 32 frames how many bits are there in the logical address?
As was given for a 4 Page, 1024 words & 64 frames (shown below) 4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2…+10=12 bits Physical memory = 10 +6 =16 bits The answer for this problem is 13. 8 pages -> 2^3 bits 1024 bytes -> 2^10 bits 32 frames -> 2^5 bits Therefore: Logical memory = 3+10=13 bits (Page + Word) Physical memory = 10 + 5 =15 bits (Word + Frame)
Bit Interval: The time required to send one signal bit. Bit Rate: The number of bits that are conveyed or processed per unit of time. (Example: 100MB/sec)
In Windows XP
Refers to native data size & processing speed, each of those potentially twice as fast provided you have Ram etc. to support.
If you mean to install Windows x64 instead of Windows X32... You will have to reinstall the OS. Even more you might have to buy 32 bit version if did not come with your comput…er.
The ISA slot started as 8-bit, and then evolved to 16-bits.
If you are using TC.EXE (or TCC.EXE) then it is 16-bit.
Which answer lists the correct number of bits associated with each term. 8 bits per double word 32 bits per word 64 bits per quadruple word or 4 bits per byte?
A person will not be able to know which answer lists the correct number of bits without knowing what the answer choices are. In order to know which of the answers is corre…ct the answer options should be given.