Which do you suppose exerts more pressure on the gound- an elephant or a woman standing on spike heels?

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Lets do a quick calculation.

A typical woman would way in at about 70 kg. If she is wearing spike heels, standing on her heels, her total surface area conveying her weight to the floor would be the sum of the area of the heels. Let's say her spike heels each have a surface area of 0,16 cm2
This would be possible is say they were 0,4 cm x 0,4 cm.

That would mean she has a total pressure of 70 kg on 0,16 cm2. This is the same as 437,5 kg pr. cm2.

Now for the elephant!

A male African elephant can weigh as much as 4.500 - 6.000 kg. For the sake of this calculation lets say the elephant weighs 5.000 kg.

An elephants foot can be as large as 40-50 cm in length and width. The circumference can be as large as 1,3 m.
From math we know that A = π x r2
We know π, but we need to know the radius, r.
This we could take from the width / length measurements, but we want to find it for a circle that has a circumference of 1.3 m.

Since O = π x d => O / π = d => d = 41,4 cm. This equals a radius of 20,7.
No we can calculate the surface area of 1 elephant foot to be π x 20,72 = 1345, 45 cm2.
Since an elephant has 4 feet, the total surface area will be 5381,8 cm2

This gives the elephant a weight to surface-area of 5000 kg on 5381,8 square centimeters of surface, which equals 0,92 kg /cm2.
Compare this to the womans which was 437,5 kg / cm2. (Though you should keep in mind, that the womans total surface area was only 0.16 cm2).

The answer is: The woman has by far the most pressure on the ground compared to an elephant. Actually she has 470 times as much pressure. This is why you want women to take of their high heels at your party, if you have wooden floors.
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Why is there more pressure under a woman's stiletto high heel shoe than an elephants foot?

Pressure is exactly equal to force divided by surface area. If that fact is true it is because the whole elephants weight (force) is spread out over four feet of relatively large surface area. A womans weight is only on her two (smaller) feet. If she leans on the back of her high heels all the weight (force) shifts to the tiny points of the stillettos. To find out how much more pressure is on the stillettos, just take the weight divided by the approximate surface area of the high heel. But since elephants weigh up to 13000 pounds, about 100 times what a woman weighs the heels would need to be (since only two heels to an elephants 4 feet) about 50 times smaller than an elephants foot to get equal pressure so it seems possible.

Does cold air exert more pressure?

It depends on the situation. In a contained vessel (eg a tyre), then hot air would exert a higher pressure. In general outside the pressure is (fairly) constant, and it is the density which changes with temperature. Imagine if this weren't true; you could have two pockets of air next to each other at different temperatures, and thus also at different pressures. In reality this leads to the pressure region expanding (and so decreasing in pressure), squashing the lower pressure region (increasing its pressure). This would continue until the pressures were the same in both regions.

What creates more pressure--the Empire State Building or a woman standing in high heels?

This is not answerable without more information. You would need to know the weight of the woman and the surface area of her heels, plus the total weight of the Empire State Building and its base area. It is conceivable that a woman in stilleto heels could exert more pressure per square inch than the building, but it takes real numbers and conditions to determine that. A 1/4" wide stilleto heel will exert 16 times as much pressure as a 1" heel, so the dimensions are important.

What does 5c stand for?

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Who exerts more pressure on the ground an elephant or a woman in spike heels?

[At the moment when only the heel rests on the ground.] Ask teams to tackle this challenge. (Stiletto heels have an area of about 1/16 of a square inch. Elephants, unlike humans, walk with two feet on the ground at a time. Each foot is about 40 square inches. Thus, the woman "wins" by far more than 1,500 psi versus 75 psi.)""Humans will only have one foot on the ground while walking. Estimate that the area of the heel on a man's shoe is 10 in 2 . When he walks, a 200 lb. man exerts 20 psi because the weight is supported momentarily by the heel. A 100 lb. woman exerts many more psi when she wears heels. Depending on the area of the heel, she can exert as much as 1600 psi under a 'stiletto heel' ¼ inch on a side. This explains why people with wood floors don't want women walking on them in high heels.""65kg on a surface of 2 cm 2 (e.g., high heel shoes) will result in a pressure of 3 250 000 Pa (beneath the high heels, if the person is standing on the surface of planet Earth). A four ton elephant, on the other hand, standing on one foot will cause a pressure of only 250 000 Pa under that foot. As an exercise try to calculate the area of the aforementioned foot. The solution can be found in this footnote1." http://hypertextbook.com/facts/2003/JackGreen.shtml

Who exerts more pressure on the ground a 50 kg woman standing in high heels or a 50 kg woman standing in work boots?

I would think that the woman in high heels would exert more pressure per square inch. All that 50 kg of weight is concentrated onto the small heels of the high heels, whereas with the boots it's spread out around the area of the boots, which significantly lowers the pressure. Put another way, if you go out and try to walk on extremely crunchy snow with the boots, they act like a pair of liferafts on water, in a sense, or at least for a second or two. With the heels, they sink right through the snow.