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Various energy losses occur in Transformers:
Copper losses, the resistance to the current flow in the windings which heats the conductors.
Iron losses, which are of two kinds:
- eddy current losses which flow in the laminations of the core caused by the magnetization and re-magnetisation of the core, which also causes heatingof the core. Eddy current losses can be greatly reduced by not making the out of a solid piece of iron.
That is why transformer cores are generally made of lots of separate thin "laminations" which are insulated from one another by being bonded together using an epoxy resin adhesive.
- hysteresis losses which are again caused by the magnetizing and de-magnetising of the core.
These are reduced by making the laminations of silicon steels, which have lower hysteresis losses than plain iron.
Together all these losses lead to a total efficiency of about 97 to 98%, which will alter depending upon the load current that the transformer is supplying.
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What is the significant relationship of the no load loss in excitation current test in transformer?
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
What is the use of ideal transformer?
Ideal transformer is useful in understanding the practical transformer..i does't have losses...
How to calculate transformer core loss and iron loss?
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
What is the reason to use open circuit and short circuit methods to find Transformer losses?
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
For 250 KVA transformer how many KVAR to be paralleled for no load loss?
No load losses are real power losses (in watts, not vars), so I'm not sure what you're talking about. If you're trying to parallel a transformer with another one to try to cancel out no load losses, you can't do this. These losses are also called core losses and are the price you pay to energize a transformer.
What will happen if iron losses and copper losses are equal for any transformer?
The transformer will have the maximum efficiency.
What is the significant relationship of the no load loss in excitation current test in transformer?
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
What is the use of ideal transformer?
Ideal transformer is useful in understanding the practical transformer..i does't have losses...
What is copper loses in transformer?
Losses due to loading. As more load (more current) is put on a transformer, these losses will increase. They are often referred to as I2R (or I^2*R) losses.
Why core losses are always fixed in transformer?
Core losses are losses in the magnetic system of the transformer, such as eddy currents in the core, hysteresis losses, etc. Because of this, the losses are constant, regardless of load, assuming voltage and frequency stay fixed.
What is the percentage load at which maximum efficiency occurs for the single phase transformer?
That is the maximum efficiency occurs when the copper losses are equal to the core losses of the transformer.
How to calculate transformer core loss and iron loss?
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
What is the reason to use open circuit and short circuit methods to find Transformer losses?
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
For 250 KVA transformer how many KVAR to be paralleled for no load loss?
No load losses are real power losses (in watts, not vars), so I'm not sure what you're talking about. If you're trying to parallel a transformer with another one to try to cancel out no load losses, you can't do this. These losses are also called core losses and are the price you pay to energize a transformer.
Which machine have very less losses in electrical?
Transformer
Why are iron losses considered as constant losses in transformer?
Iron losses are due to energization of the transformer; they do not depend on the loading of the transformer. They will vary depending on the voltage applied to the transformer. The best model of this is a parallel connection to the ideal transformer winding.
How is copper losses reduced in transformers?
how to reduce copper losses in a transformer Copper losses are due to the resistance of the copper (or aluminum) windings. To reduce copper losses the transformer would have to be rewound with heavier gage wire.
