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No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electron…s (each has 7 own plus 1 from boron). (MORE)
Si has four valence electrons and fluorine has seven. After forming four Si-F bonds, all atoms will get eight valence electrons and this compound follows the octet rule.
Yes, it obeys the octet rule. (Of coarse not an octet for the H atoms: they are saturated with a duplet (=2)). To show you HOW this is done, you will need the structural for…mula: If it is a monosaccharide there are already 32 different isomeres. And even one of these and the most common one: alpha-D-gluco-pyranose (which is glucose) is too difficult to draw it in this simple 'html-text editor' layout. Just as example some explaining calculation about electron bonding pairs and free pairs. Valence electrons counting: 6 C = 6x4 = 24 e 12 H = 12x2 = 24 e 6 O = 6x6 = 36 e Total of 84 electrons are available for free or covalent (= bonding) electron pairs (total 84/2 = 42 pairs can be formed) Needed for octets and H-duplets 6 C = 6x8 = 48 e 6 O = 6x8 = 48 e 12 H = 12x2 = 24 e Total needed for octets/duplets = 120. These are 60 'needed to see' pairsC has no free pairs, all 4 are covalent pairs (= 1 octet): 6x4 = 24 covalent bondsO has 2 free and 2 covalent pairs (= 1 octet): 6x2 = 12 covalent bondsH has no free pairs and 1 covalent pair (= 1 duplet): 12x1 = 12 covalent bonds Total of 24 double counted bonding pairs (48 pairs 'seen' from one atom AND 'seen' from the other atom bound to it, called covalent*) electron pairs) One possible structure (which is not glucose) fitting the above calculation (1, 2, 3) is described here: 6 C atoms in a regular (bee hive) ring: 6 covalent pairs 6 H atoms directly to each C: 6 cov. pairs 6 O atom bonded at one side to each C atom: 6 cov. pairs 6 H atoms bonded to the other side of those 6 O atoms: 6 cov. pairs Total of 24 double counted bonding pairs*) between all atoms. This leaves 6x2 = 12 free electron pairs, two per O atom to fulfill their 'octet need' And now you can conclude: 24 double counted = 48 'seen' electron pairs which are covalent*) 12 free electron pairs (2 on each O atom) Total of 60 'structural drawn' pairs, Thus this, being the same as the 'needed to see' pairs (60, see above), means that ALL atoms are obeying the octet (+ duplet) rule. *) covalent means: 'seen by two' atoms which are bound together. (The name of this formula would be 1,2,3,4,5,6-cyclo-hexane-hexa-ol, it isn't even a monosaccharide) (MORE)
For PC games that require a little more control than what your keyboard and mouse can provide, you may want to consider buying a game controller. Before you buy the first game… controller you see online, check out the following PC game controller reviews from this list. If you want (MORE)
Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted corre…ctly!): .......O.......| O -- S -- O .......|| .......O Hope this helped! (MORE)
No. The boron atom is electron deficient. It only has 6 outer shell electrons in this molecule.
Beryllium does not obey the octet rule, as it is one of the exceptions. Other exceptions include: H, He, Li, and B