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I know for sure BBr# & PF5 do not obey the octet rule, but i can't remember the rule of isotopes so I can't say for sure whether or not CO3 -2 obeys it or not.
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First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has …an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electr…ons (each has 7 own plus 1 from boron).
Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted corre…ctly!): .......O .......| O -- S -- O .......|| .......O Hope this helped!
It gains electrons!
all molecules except the group 2 and group 3 molecules of the elements
No, it is the extension of octet rule due to involvement of 'd' orbitals of Phosphorus.
Yes, CS2 Obeys the Octet rule. C double bonds with both Sulfur atoms and then each S has two pair of free electrons.
No. The boron atom is electron deficient. It only has 6 outer shell electrons in this molecule.
Cs2 and Co3 2 obey the octet rule. the others don't