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This is because the elements in the first period only use their s orbitals, youll notice that Hydrogen is 1S and exists as the diatomic H2 and that Helium has the configuratio…n 2S and exists as free Helium. The reason for this is that any S orbital can only hold two electrons, the octet rule applies when there are S and P orbitals present which can hold up to 8 electrons( 2 from the S orbital and 6 from the D orbital). (MORE)
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electron…s (each has 7 own plus 1 from boron). (MORE)
hydrogen atoms have only one shell( K-shell) which can accommodate only two electrons. Therefore each hydrogen atom in hydrogen moleculecontributes one electron forming a pair… which is shared between the two atoms. Thus in hydrogen molecule duplet rule is followed and not the octet rule. (MORE)
For PC games that require a little more control than what your keyboard and mouse can provide, you may want to consider buying a game controller. Before you buy the first game… controller you see online, check out the following PC game controller reviews from this list. If you want (MORE)
You can see this happen in the F2 molecule. Each fluorine atom shares a valence electron with the other fluorine atom. So there is just one covalent bond.
Yes, it obeys the octet rule. (Of coarse not an octet for the H atoms: they are saturated with a duplet (=2)). To show you HOW this is done, you will need the structural for…mula: If it is a monosaccharide there are already 32 different isomeres. And even one of these and the most common one: alpha-D-gluco-pyranose (which is glucose) is too difficult to draw it in this simple 'html-text editor' layout. Just as example some explaining calculation about electron bonding pairs and free pairs. Valence electrons counting: 6 C = 6x4 = 24 e 12 H = 12x2 = 24 e 6 O = 6x6 = 36 e Total of 84 electrons are available for free or covalent (= bonding) electron pairs (total 84/2 = 42 pairs can be formed) Needed for octets and H-duplets 6 C = 6x8 = 48 e 6 O = 6x8 = 48 e 12 H = 12x2 = 24 e Total needed for octets/duplets = 120. These are 60 'needed to see' pairsC has no free pairs, all 4 are covalent pairs (= 1 octet): 6x4 = 24 covalent bondsO has 2 free and 2 covalent pairs (= 1 octet): 6x2 = 12 covalent bondsH has no free pairs and 1 covalent pair (= 1 duplet): 12x1 = 12 covalent bonds Total of 24 double counted bonding pairs (48 pairs 'seen' from one atom AND 'seen' from the other atom bound to it, called covalent*) electron pairs) One possible structure (which is not glucose) fitting the above calculation (1, 2, 3) is described here: 6 C atoms in a regular (bee hive) ring: 6 covalent pairs 6 H atoms directly to each C: 6 cov. pairs 6 O atom bonded at one side to each C atom: 6 cov. pairs 6 H atoms bonded to the other side of those 6 O atoms: 6 cov. pairs Total of 24 double counted bonding pairs*) between all atoms. This leaves 6x2 = 12 free electron pairs, two per O atom to fulfill their 'octet need' And now you can conclude: 24 double counted = 48 'seen' electron pairs which are covalent*) 12 free electron pairs (2 on each O atom) Total of 60 'structural drawn' pairs, Thus this, being the same as the 'needed to see' pairs (60, see above), means that ALL atoms are obeying the octet (+ duplet) rule. *) covalent means: 'seen by two' atoms which are bound together. (The name of this formula would be 1,2,3,4,5,6-cyclo-hexane-hexa-ol, it isn't even a monosaccharide) (MORE)
Yes, SO4 2- can be drawn without violating the octet rule. It is also a resonance structure. Here's an illustration below (ignore the dots, it was the only way it posted corre…ctly!): .......O.......| O -- S -- O .......|| .......O Hope this helped! (MORE)