I was unable to discover any citation about PbI2 before 1885 (Lehmann); but probably the first preparation is older.
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
Lead(II) iodide is yellow in colour
Lead (II) iodide Transition metals always need roman numerals to represent their charges.
Lead (II) iodide is PbI2. Lead (IV) iodide is PbI4.
Lead(II) iodide is yellow in colour
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
The name of compound Pbl2 is lead(II) iodide.
Produces yellow Lead(II) iodide and Sodium nitrate
Lead(II) iodide and Sodium nitrate
It produces Potassium nitrate and Lead iodide