Liquid is more dense than air. This causes it to support more weight and require less effort to lift.
When the block of wood submerges, it sinks until the buoyant force of water is equal to the block's weight.
The weightlessness is due to the buoyancy force acting on the body, it pushes the body upwards i.e in a direction opposite to that of the attraction of the earth.
The mass of the water disperses the mass of the object.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
Water helps lift an objects via the buoyancy force. The buoyancy force is equal to the weight of water displaced by the volume of the submerged object. If this buoyancy force is equal to the weight of the object, the object will float in that position. If the object is completely submerged and the resulting buoyancy force is less than the weight of the object, it will continue to sink.
They are equal.
I think you mean a buoyant force. When an object is submerged into a liquid, the liquid pushes up on the object with a force equal to the weight of the amount of fluid that is displaced.
Two ways to do this: 1) Floating the less dense object on the more dense liquid. To verify the Archimedes principle you need to show that the mass of the liquid displaced by the less dense object is equal to the mass of the less dense object. To do this you need to have a way to determine the mass of the displaced liquid. If the liquid is in a container filled to the brim, then when you place the less dense object in it, the displaced liquid will spill out over the edges of the container. If you can collect and weight that liquid, then you can compare its weight to the weight of the less dense object - they should match. Alternatively, you can find a way to measure the volume of the displaced liquid and calculate the mass from the volume and density of the displaced liquid. 2) Immerse the object completely in the liquid and measure the force required to keep it submerged. This one is more complicated and difficult to execute and measure. The force required to keep the less dense object submerged should be the difference between the weight of the object (when it is not in the liquid) and the weight of the displaced liquid.
You will find that such an object will weigh its weight on land minus the weight of the water it displaceswhen submerged. It doesn't seem possible, but it is true. This kind of result is called 'counterintuitive'.
mass of fluid, weight of fluid, density of fluid.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
That completely depends on the object's volume (which you have not mentioned). The buoyant force on it is equal to the weight of an equal volume of water.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
The buoyant force on any object in a fluid ... whether partially or fully submerged ... isequal to the weight of the fluid displaced by the object. That's related to the object'svolume, and has nothing to do with its weight.
The buoyant force on any object in water is equal to the weight of the displaced water, regardless of how much of the object is submerged.
No.
The object's own weight is pulling it down.
No, it is equal in volume.
On its volume.
Water helps lift an objects via the buoyancy force. The buoyancy force is equal to the weight of water displaced by the volume of the submerged object. If this buoyancy force is equal to the weight of the object, the object will float in that position. If the object is completely submerged and the resulting buoyancy force is less than the weight of the object, it will continue to sink.