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Salt is made up of charged ions, namely the sodium (Na+) and chloride (Cl-). The balloon repels one of the two ions, but more strongly attracts the other.

Most of us know how opposite charges attract and like charges repel (if you didn't, you do now), so consider the balloon as being, for instance, positively charged (the charge we choose does not matter, as we simply consider the ions as acting in the opposite manner to how I shall describe). The positive charge pushes the sodium ions in the salt crystals slightly away from it, whilst pulling the negative chloride ions towards it a small amount. It is important to consider only small changes, as the ions are held fairly rigidly in the ionic lattice structure in the salt, and we are not tearing apart the individual components of the crystals with something as rudimentary as an inflated sack of rubber we've been rubbing on our head for a few seconds - think of the chaos. However the difference in distances between the centres of positive and negative charge and the balloon have a significant effect. The centre of positive charge is further from the balloon than the negative charge (though by a small amount). Therefore the force of attraction overcomes that of repulsion, as the magnitude (size) of the force is determined both by the magnitude of the charges involved (which are equal as the overall charge of salt should be 0/uncharged - ie same amount of negative chloride as positive sodium - and the balloon has a charge that is used in both calculations) and on the distance. Think of a magnet and a paperclip: the further you are, the less force between the magnet and paperclip, the closer you are, the greater this force - ie you bring a magnet towards a paperclip in order to lift it up from a table, say. Therefore adding these forces together results in the salt being slightly attracted to the balloon.

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Q: Why does a charged balloon attract the salt?
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