In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
No. The larger the conductor the lower the resistance and the higher the ampacity.
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
1. The sum of the component voltage drops in a series circuit is equal to the voltage at the source.Vs=V1+V2+...+Vn (s=source, n=total number of voltage drops in the circuit)2. The greater the resistance imposed by a component, the greater the voltage drop across it.Larger resistor=larger voltage drops, Smaller resistor=smaller voltage drops3. In a series circuit, the percentage of resistance contributed by a component is equal to the percentage of voltage dropped by that component.
A load is anything that draws current from a source of potential difference. A 'heavy' load will draw a larger current than a 'light' load. A resistor can certainly be used as a load. A low resistance will draw a larger current than a higher resistance and, so, a low resistance represents a high load while a high resistance represents a low load.
A pipe. The volume of water available can be compared to voltage. The diameter of pipe could be compared to resistance with smaller diameter being larger resistance and the flow of water past a point in pipe is equivalent to current flow.
No. The larger the conductor the lower the resistance and the higher the ampacity.
Ohms law is: V = I x R (voltage = current x resistance) ... therefore the larger the resistance the larger the voltage drop across that resistance.
A voltmeter has the large resistance.The voltage across any component can be measured if & only if the terminals of that component will be open and this will we can acheiv if we connect the high resistance voltmeter across the open terminals of that component to measure the voltage.
As the resistance in the wire increases due to the longer length the voltage drop across the wire resistance increases. This leaves less voltage across the load. To overcome this voltage drop usually a larger size wire which has less resistance is used. A safe nominal figure for voltage drop is to keep it at 3% of the line voltage.
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
Yes. For a condition called 'series resonance', if the resistance of the circuit is low compared with the inductive reactance and capacitive reactance, then the voltage drop across the capacitor can be VERY much higher than the supply voltage.
In a closed circuit there is a potential drop due to resistance of wires and battery (internal).AnswerWhen the circuit is closed, the resulting current not only flows through the external circuit, but through the source (battery, generator, transformer, etc.) itself. All sources have an internal resistance, which causes an internal voltage drop, slightly reducing the voltage across the terminals. The larger the current, the larger the internal voltage drop, and the lower the terminal voltage.When the circuit is open, no current flows. So there is no internal voltage drop, and the full voltage appears across the source's terminals.The 'open-circuit voltage' is actually the electromotive force provided by the source.
Greater value resistor will absorb more voltage than smaller value. The more voltage absorb with same value current flow, the larger body mass resistor will require. Body size depends on type of resistor (material resistor is made of).
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
1. The sum of the component voltage drops in a series circuit is equal to the voltage at the source.Vs=V1+V2+...+Vn (s=source, n=total number of voltage drops in the circuit)2. The greater the resistance imposed by a component, the greater the voltage drop across it.Larger resistor=larger voltage drops, Smaller resistor=smaller voltage drops3. In a series circuit, the percentage of resistance contributed by a component is equal to the percentage of voltage dropped by that component.
A load is anything that draws current from a source of potential difference. A 'heavy' load will draw a larger current than a 'light' load. A resistor can certainly be used as a load. A low resistance will draw a larger current than a higher resistance and, so, a low resistance represents a high load while a high resistance represents a low load.