Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
Being Colorblind means you recieved 2 recessive alleles from you parents. So that means the mother and father must of had 2 recessive alleles. Also Colorblindness is more common in males.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
An allele that is always expressed when it is present is the dominant allele.
The dominant allele.
It overpowers and masks the other allele
The Dominant allele hoped this helped! :)
YES ALWAYS!!! Even if you have for example, Aa (A being the dominant allele and a being the recessive allele) that trait will always be dominant!
The type of allele known for skipping a generation is the recessive allele because it is almost always hidden.
A dominant allele is an allele that can take over a recessive allele, so if you have a dominant allele and a recessive allele, then the offspring will most likely have a dominant allele over a recessive allele. The dominant allele is expressed over the recessive allele.
A dominant allele is a gene that holds a certain characteristic that is superior to a recessive allele. The dominant allele ALWAYS has its trait shown in the body of the recipient, except when both alleles in a gene are recessive.
type 2 Diabetes
The ratio of colorblindness of men to women anywhere is virtually 1:0. Colorblindness is a sex-linked disease and you have to know a little biology to know why men account for almost 100% of the world's colorblind population. See, at birth, the genes of the mother and father fuse together to produce the offspring. The male sex gene is XY while the female is XX. So if the offspring is male, the offspring receives a Y from its father and an X from its mother (since the mother can only give Xs). And if the offspring is female, the offspring will receive an X from both parents. So the chance of having either a boy or a girl is always 50/50 and it comes down to what the father gives. Colorblindness is a sex-linked disease, as mentioned earlier, which means its coded on the sex genes. Sex-linked diseases are almost always located on the X chromosome. And to get this gene, you must have 100% of your Xs coded for it. A female could become colorblind only if she receives an X from both parents that code for the disease. A male could become colorblind if he receives an X from his mother that codes for the disease. So it is a much greater chance for males to become colorblind than females, because every rarely does it happen that a female receives a sex-linked disease. However, a woman can still receive a gene that codes for the disease. If she receives just one, she is a carrier of the disease and may pass it on to her offspring. If she receives two, she has the disease. If she receives none, she's free of the disease.