Actually it is about the orbitals of valence shells of sulphur. Sulphur has atomic no. 16 and electronic configuration 1s2,2s2,2p6,3s2,3p4. Its outer most shell has s.p.d and f orbitals from which s and p have electrons and d and f are vacant.
When 2 electrons from p are transferred to d, the valency becomes +2.
When two more electrons from p are transfered to d, the valency becomes +4.
When two left electrons from s are transferred to d, the valency becomes +6.
Because sulfur is +6 (6 valence electrons) but there are 4 oxygens at -2 bound to it so its net charge is +6 - 4 x -2 = -2
38.
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
S = +6 valency O = -2 valency
Sulfur can have a wide range of oxidation in its compounds -2 in H2S 0 in elementary sulfur (S8) +4 in SO2 +6 in SO3
Because sulfur is +6 (6 valence electrons) but there are 4 oxygens at -2 bound to it so its net charge is +6 - 4 x -2 = -2
+6 valency
2, 3, 4, 6.
38.
Oxygen is divalent, but sulphur exhibits variable valency of 2, 4 and 6 because of the presence of d -orbitals in sulphur. In sulphur, the excitation of np -electrons to nd -sub-shell gives rise to increase in number of unpaired electrons. Option D is correct.
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
S = +6 valency O = -2 valency
Possible valences are (+1), +2, (+3), +4, +6
Sulphur
valency of Rf =4 valency of Db=5 valency of Sg=6 valency of Bh=7 valency of Hs=8 valency of Mt=unknown
It is different compound to compound. Sulfur generally shows +6 and +4.
there are 6 electrons in valence shell of sulphur so it accepts two electrons to complete the octet (8 electrons in last shell) so its valency in ionic compounds is always - 2.