It is possible for a 2000 Passat 1.8L to interchange with a 1999 version. However, the interchanged numbers must match the older version it is being replaced with.
18L per 100km equates to 13 miles per gallon!
Use the radio's volume and frequesce setting buttons next to the clock.
It is a V-8 18L
18 l is greater.
There are 36 units of 250 ml in 18 litre
It takes an experienced mechanic about three hours to change from start to finish. You may be able to find a good used turbo for about $400, the new gaskets will be about $80. A new turbo is around $900. Check rockauto.com for good parts prices, I've had good luck there, also vwvortex.com
I have a 2001 1.8T Passat Station Wagon. My (non-dealer) repair shop suggests that premium gas is only required for city driving. When going on a long trip with mostly high speed interstate driving, mid-grade gas is okay according to them. I have been following their advice for the last year and have had no change in gas mileage or performance. As a once owner of a 2000 Passat wagon, a brother-in-law who has spent over the last 20 years as a VW dealer tech and he too still owns his 2000 Passat wagon 1.8T has never used anything but regular unleaded gas in his car. He says there is no reason that he has ever known or experienced in his many years as a tech and owner to use premium gas in this car. With the 1.8T you should only be using a full synthetic oil. there is no way around this. Using conventional motor oil WILL cause sludge in your engine, void the extended warranty on this engine and cost thousands to fix.
Nissan 18L can you put super4 spark plugs
there is no difference unless you are referring to the Northrop Grumman F-18L and the McDonnell Douglas F/A-18
I found this site, http://installdr.com/InstallDocs/Acura/Integra.html, hope it helps.
The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.
18000mL is 18L (divide mL by 1,000).1800 ml = 1. 8 liter