In theory, if a bullet dropped vertically at the same instant that a bullet is fired horizontally from a gun at the same height, they should both hit the ground at the same time.
This example is used to emphasize that that horizontal motion and vertical motion may be analysed separately since they occur independently of each other.
This is one of those things that works better in theory than in practice.
There is a caveat that is important if you consider doing this in the real world. The process is not happening in a vacuum. The aerodynamics of the bullet fired at high speed is tremendously important. In early gun design, this was not understood and bullets fired from guns were very inaccurate and went up or down or right or left in unpredictable ways. Modern guns stabilize the trajectory by putting a spin on the bullet. The result makes the bullet act like a gyroscope and then to remain pointed forward when it encounters small anomalies in the air and wind. So, the moving bullet is subjected to vertical forces and can not be expected to drop at the same rate as a bullet with no horizontal motion.
The principle of independent horizontal and vertical motion works better when illustrated by throwing and dropping heavy rocks. The principle is entirely correct, but there are more vertical forces involved than gravity with the bullets.
The answer is obvious. The bullet fired from the gun will reach the ground faster than the bullet dropped from the same height.
This would be because the bullet fired from the gun would have a higher initial velocity. The bullet dropped from the gun will have no initial velocity.
The bullet is fired vertically upwards (away from the ground).Again, obvious. The bullet fired will take a longer time to fall down than the dropped bullet.
This is because the bullet has to first travel upwards and then downwards, and hence will have more distance to cover.
The bullet is fired perfectly horizontal.If the bullet is fired perfectly horizontal to the ground, the fired bullet and dropped bullet will hit the ground at the same time.
The reason is that the force of gravity is a constant, so the bullet will be pulled down vertically at the same speed, regardless of its horizontal speed.
Note for Case 3:
In theory, it will do so, but only in a perfect vacuum when the bullet is fired exactly parallel to the ground. The reason for my caveats are that, in a vacuum, there is no air friction, which might tend to affect the fired bullet more than the falling bullet, nor any ability to for the fired bullet to rise aerodynamically (like the wing of an airplane).
If the bullet is shot perfectly horizontally, and the land in the direction of the shot
is perfectly flat, and both begin at exactly the same distance from the ground,
and there is no air in the way to interfere with the bullet's vertical motion, then
both bullets will hit the ground at the same time.
The horizontal motion of the bullet is independent of the vertical motion. Both
bullets are acted upon equally by gravity and will fall at the same rate. Because
the one bullet is also moving horizontally, it will strike the ground far from the
bullet that is dropped.
Provided the ground way out in front of the rifle is at the same elevation as the ground
under the gun's barrel, both bullets hit the ground at the same instant.
(What I mean is . . . if the rifle fires into the side of a mountain, or off the edge of a cliff, then
of course they don't hit the ground at the same time. The point is that both the dropped bullet
and the fired bullet fall the same vertical distance in the same amount of time, regardless of the
big difference in their horizontal speeds.)
they will hit the ground at the exact same time(if the terrain is flat, but the earth is round so if you consider the roundness of the earth, the one that is dropped will hit the ground first).
Yes both fall at the same time provided the friction due to air is not taken into account. If air friction is to be considered then there will be a slight difference. Horizontal one would take a little bit larger duration than the vertical one
YES! they will fall at the same time...according to my science teacher. So you should test that out one of these dayys. it sounds exciting.
dropped
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
The bullet dropped .1612 meters. To solve this type of problem, first determine how much time it took the bullet to travel to the target. Since Velocity = Distance / Time, Time = Distance / Velocity. In this problem Time = (50 m) / (275 m/s) = .1818 seconds. Now use this time to figure out how far the bullet would have fallen due to gravity. You've probably seen this equation (or something like it) before: Δy = vo*t - 1/2 * g * t2. This equation means that to find how far the bullet fell you need to know how long it was falling, how fast it was falling at the very beginning, and what the acceleration due to gravity is. We already figured out how long the bullet was falling, we know that it wasn't falling at all at the very beginning, and gravity = 9.8 m/s2. This means that: t = .1818 vo = 0 g = 9.8 So plug that in to the previous equation: Δy = (0) * (.1818) - (1/2) * (9.8) * (.1818)2. Δy = - .1612, with the - sign meaning the bullet went down and not up into the air.
The first bullet point of the male (human):Generally, males are taller and have bigger upper body muscles than females.
Probably the heaviest
Probably the heaviest
Both hit at the same time.
Please describe how you drop something 'horizontally'
A bullet fired parallel to the gound, over flat ground, and a bullet dropped at the same time from same height will hit the ground at a time so close to each other as to be the same.
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
they hit same time
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
To a first approximation, over short distances horizontal motion is decoupled from vertical motion. If you fire a bullet horizontally from a gun, and drop a bullet from next to the gun at the same time, both bullets will hit the ground at the same time. Over long enough distances the curvature of the Earth begins to have an effect, so this is no longer true.
Depends on rifle, bullet, case design and powder charge.
They should reach the ground together, since their initial vertical speed is the same, namely zero.
A cannonball fired horizontally and one dropped from the height of the muzzle simultaneous with the shot will hit the ground at the same instant, provided only that the ground under the muzzle and the ground where the shot lands are at the same elevation, i.e. the shot was not fired off the edge of a cliff or into the side of a mountain. To solve this kind of problems, it often helps to separate the movement, or the speed, into vertical and horizontal components. In this case, the vertical component of the speed is the same.
Depends on which one is dropped first. If they are both dropped at the same time, they will both reach the ground at the same time.