The "air fuel plug" is an oxygen sensor. It works by sending between 0 and 1 volt to the cars computer. Putting a resistor on the O2 sensor will not add horsepower; most O2 sensors cannot produce more than 1 volt. If a resistor is added it will cause the car to register more rich so it will add less fuel and actually run lean. Running lean will cause higher combustion temprature and in the long term cause premature seal failier. Its a stupid idea....take the time to browse the forums and figure out some mods that have been done by others. Do not add any resistors to the car for the reason of "adding performance" (eg. MAF, water temp) they will not any real HP, WILL cause harm to the car, and you will make all of us other 240 guys look bad. -keys
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
Since you're checking the resistor, I would assume you checked the fuse/relay for the blower motor. If not check that. If you have then there would be an open wire between the relay and the resistor.
The current would be about 20 volts.
In order to determine this, it will be necessary to find which resistor 'maxes out' at the lowest voltage. This can be found using the equation Vi=sqrt (Pi*Ri) for each resistor, where Pi is the power rating of resistor i and Ri is the value of resistor i. Once this is found, the power dissipation of each other resistor can be found using the equation Pi=(Vl^2)/Ri, where Vl is the voltage that maxes out the resistor which maxes out at the lowest voltage, and Ri is the resistance of each resistor. The equivalent power rating would then be the sum of the power dissipated across each resistor.
You need more information to find out how much horse power there would be. There would be a variety of horse power concerning what engine the turbo was on.
Need more information - a typical regulated power supply would include dozens of resistors, each for one of several different reasons. Which resistor are you asking about?
The power rating of a resistor determines how much power it can dissipate without being damaged. For example, a 1/4W resistor is designed to handle up to 1/4W continuously without being destroyed. When selecting a resistor to use in a circuit, use Ohm's law to calculate the power it will dissipate. For example, placing a 1kΩ resistor across a 12VDC signal will allow 12/1000 = 0.012A to flow thru the resistor. 0.012*12 = 0.144W will be dissipated. Thus, a 1/8W (0.125W) resistor would not be sufficient, and a 1/4W (0.25W) must be used.
if it had no engine
1/2 watt (In theory you could use a "0.27 Watt" resistor, however there would be no safety factory and there is no standard value resistor that size.)
it really depends on what engine you put on it if you out a 6.5 hp on it it would have that much horse power.
The car or scooter as a out of 50bhp brake horse power so with this horse power you would not be allowed on the motaway with that
Depends on their power rating. 50 volts across a 50 ohm resistor means 1 amp, 50 Watts, which would need quite a big resistor to deal with that power.