Answered

In English Spelling and Pronunciation

# How do you spell hor' derves?

\nHors d'oeuvres is the English plural, hors d'oeuvre is the English singular.\n.
\nHors d'Åuvre is the French plural and the French singular.

Answered

In English Spelling and Pronunciation

\nHors d'oeuvres is the English plural, hors d'oeuvre is the English singular.\n.
\nHors d'Åuvre is the French plural and the French singular.

Answered

In English Spelling and Pronunciation

Hors d'oeuvres (appetizers) is the English plural, hors d'oeuvre is the English singular. (Hors d'Åuvre is the French plural or singular.)

Answered

In The Battle of Hastings

In my opinion I think that Harold of Wessex deserved to win because during the first two years King William suffered many revolts throughout England, so many people wanted Har…old of Wessex to be king. If Harold of Wessex won the battle of Hastings I think that he would have looked after his people as he is wealthy. hope that answers your question ( Full Answer )

Answered

In Math and Arithmetic

For the function: y = x^x^x (the superscript notation on this text editor does not work with double superscripts) To solve for the derivative y', implicit differentiation… is needed. First, the equation must be manipulated so there are no x's raised to x's on the right side of the equation. So, both sides of the equation must be input into a natural logarithm, wherein we can use the properties of logarithms to remove the superscripted powers of the right side: ln(y) = ln(x^x^x) ln(y) = x x ln(x) ln(y)/ln(x) = x x ln(ln(y)/ln(x)) = xln(x) e ln(ln(y)/ln(x)) = e xln(x) ln(y)/ln(x) = e xln(x) ln(y) = ln(x)e xln(x) Now there are no functions raised to functions (x's raised to x's). Deriving this equation yields: (1/y)(y') = ln(x)e xln(x) (x(1/x) + ln(x)) + e xln(x) (1/x) = ln(x)e xln(x) (1 + ln(x)) + e xln(x) (1/x) = e xln(x) (ln(x)(1+ln(x)) + (1/x)) Solving for y' yields: y' = y[e xln(x) (ln 2 (x) + ln(x) + (1/x))] or y = x x^x ln(y) = ln(x) x^x ln(y) = x x ln(x) ln(y) = e xlnx ln(x) y'/y = e xlnx [ln(x) + 1)ln(x) + e xlnx (1/x) y' = y[e xlnx (ln 2 (x) + ln(x) + 1/x)] y' = x x^x [e xlnx (ln 2 (x) + ln(x) + 1/x)] ( Full Answer )

Answered

In English Spelling and Pronunciation

The spelling "Derves" is an uncommon surname. The spelling hors d'oeuvres is the English form of the French word for appetizers.