1948 Davis Cup
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1948 Davis Cup
The 1948 Davis Cup was the 37th edition of the most important tournament between national teams in men's tennis. 29 teams would enter the competition, 25 in the Europe Zone, and 4 in the Americas Zone.
Australia defeated Mexico in the Americas Zone, and Czechoslovakia defeated Sweden in the Europe Zone. Australia defeated Czechoslovakia in the Inter-Zonal play-off, but fell to defending champions the United States in the Challenge Round. The final was played at the West Side Tennis Club in Forest Hills, NY, United States on 4-6 September.
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Contents
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Americas Zone
Draw
| 1st Round July |
Final 6-8 August |
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| Havana, Cuba | ||||||||||
 Australia |
5 | |||||||||
 Cuba |
0 | Mexico City, Mexico (clay) | ||||||||
| Australia |
4 | |||||||||
| Montreal, Canada (grass) |  Mexico |
1 | ||||||||
 Canada |
1 | |||||||||
| Mexico |
4 | |||||||||
Final
 Mexico 1 |
Centro Deportivo Chapultepec, Mexico City, Mexico 6 August - 8 August 1948 clay |
 Australia 4 |
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Europe Zone
Draw
Final
 Czechoslovakia 4 |
Prague, Czechoslovakia 27 July - 29 July 1948 |
 Sweden 1 |
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Inter-Zonal Zone
Czechoslovakia 2 |
Longwood Cricket Club, Boston, MA, United States 19 August - 22 August 1948 grass |
Australia 3 |
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Challenge Round
 United States 5 |
West Side Tennis Club, Forest Hills, NY, United States 4 September - 6 September 1948 grass |
Australia 0 |
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